3 years ago

PLEASE HELP What are the zeros of function f(x)=x^2+5x+5 written in simplest radical form?

1 answer:

3 0

Your answer is the third option.

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fredd [130]

I see your doing trinomials. It would be prime because nothing <span>adds to negative ten and multiplies to six.</span>

7 0

3 years ago

Leya [2.2K]

The answer to your question is y= -2/5x + 8/5

5 0

3 years ago

fenix001 [56]

Answer:

-2x^2 - 2

Step-by-step explanation:

(6x^2 + 3) - (5 + 8x^2)

-2x^2 + 3 - 5

-2x^2 - 2

3 0

3 years ago

ivolga24 [154]

Let us suppose, we pour x glass of water.

The given jug is of 6 liters. And the glass of water was seven- eighths of a liter. Hence, we have the below equation

$\frac{7}{8} x= 6$

Now, in order to solve for x, we will divide 6 with 7/8. So, we have to divide.

$x=\frac{6}{7/8} \\
\\
x=\frac{48}{7} \\
\\
x=6.9$

Hence, we can pour 7 glass of water. But the 7th glass is not full of water. It is partially full.

5 0

3 years ago

olga2289 [7]

$\frac{\big{8}}{\big{24}} = \frac{\big{8:8}}{\big{24:8}} = \frac{\big{1}}{\big{3}}$

5 0

3 years ago