2. Solve: 33 + 2(5+8)-(6-2)

Mathematics

1 answer:

mars1129 [50]3 years ago

6 0

Answer:

Step-by-step explanation:

Add the numbers 5 + 8 and you get 13. Multiply 13 x 2 which is 26. Add 33 + 26 and you get 59. Then, subtract it by 4 and you get 55.

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Need this ASAP please help!#2

myrzilka [38]

Answer:

The correct option is 3.

Step-by-step explanation:

From the given graph it is noticed that the related line passing through the point (-3,1) and (0,3).

If a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of related line is

$y-1=\frac{3-1}{0-(-3)}(x-(-3))$

$y-1=\frac{2}{3}(x+3)$

$y-1=\frac{2}{3}(x)+2$

Add 1 on both the sides.

$y=\frac{2}{3}(x)+2+1$

$y=\frac{2}{3}(x)+3$

The equation of related line is $y=\frac{2}{3}(x)+3$ .

The related line is a dotted line, it means the point on the line does not included in the solution set.

The shaded region is above the line so the sign of inequity is >.

The required inequality is

$y>\frac{2}{3}(x)+3$

Therefore option 3 is correct.

6 0

3 years ago

Answer Question number 5 Plzzzzzz

loris [4]

Answer:

Step-by-step explanation:

a = -4/3

d= -1 +4/3 =1/3

last term = 4 1/3 = 13/3

nth term = a +(n-1)d

$\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18$

Middle terms are 9the term and 10th term

$t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3$