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Keith_Richards [23]
3 years ago
14

The price of grapes, g, is $2.19 per pound. The price of bananas, b, is $0.59 per pound. The price of pears, p, is $1.49 per pou

nd.
Part A
Write an expression to represent the total price of the fruit. Drag numbers to complete the expression.
0.591.492.19
g +
b +
p

00:00

Part B
What is the total cost for 3 pounds of grapes, 3 pounds of bananas, and 2 pounds of pears? Enter your answer in the box.

$
Mathematics
1 answer:
AlekseyPX3 years ago
3 0
Part A.
Before you can write any sort of expression, you need to define variables. "grapes g" is not a definition, so the exercise seems meaningless as written. It seems the intent is to ...
  let g, b, p represent the numbers of pounds of grapes, bananas, and pears, respectively.

Then, the total cost of some weight of fruit is
  2.19g + 0.59b + 1.49p


Part B.
For g=3, b=3, p=2, the expression evaluates to
  2.19*3 +0.59*3 +1.49*2 = 11.32

The total cost of 3 pounds of grapes, 3 pounds of bananas, and 2 pounds of pears is ...
  $11.32
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Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

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Given G(4,3), H(1,0)

|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}

Given E (−2, 3), H (1, 0)

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<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|=\frac{6-3}{1+2} =\frac{3}{3}=1

Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

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Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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