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crimeas [40]
4 years ago
13

3x-7y=-28 Need help solving the question

Mathematics
1 answer:
Valentin [98]4 years ago
7 0
P.p1 {margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px 'Helvetica Neue'; color: #454545} p.p2 {margin: 0.0px 0.0px 0.0px 0.0px; font: 12.0px 'Helvetica Neue'; color: #454545; min-height: 14.0px}

Simplifying

3x + 7y = 28


Solving

3x + 7y = 28


Solving for variable 'x'.


Move all terms containing x to the left, all other terms to the right.


Add '-7y' to each side of the equation.

3x + 7y + -7y = 28 + -7y


Combine like terms: 7y + -7y = 0

3x + 0 = 28 + -7y

3x = 28 + -7y


Divide each side by '3'.

x = 9.333333333 + -2.333333333y


Simplifying

x = 9.333333333 + -2.333333333y

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Determine the maximized area of a rectangle that has a perimeter equal to 56m by creating and solving a quadratic equation. What
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Answer:

Area of rectangle = 196\,m^2

Length of rectangle = 14 m

Width of rectangle = 14 m

Step-by-step explanation:

Given:

Perimeter of rectangle is 56 m

To find: the maximized area of a rectangle and the length and width

Solution:

A function y=f(x) has a point of maxima at x=x_0 if f''(x_0)

Let x, y denotes length and width of the rectangle.

Perimeter of rectangle = 2( length + width )

=2(x+y)

Also, perimeter of rectangle is equal to 56 m.

So,

56=2(x+y)\\x+y=28\\y=28-x

Let A denotes area of rectangle.

A = length × width

A=xy\\=x(28-x)\\=28x-x^2

Differentiate with respect to x

\frac{dA}{dx}=28-2x

Put \frac{dA}{dx}=0

28-2x=0\\2x=28\\x=14

Also,

\frac{d^2A}{dx^2}=-2

At x = 14, \frac{d^2A}{dx^2}=-2

So, x = 14 is a point of maxima

So,

y=28-x=28-14=14

Area of rectangle:

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Length of rectangle = 14 m

Width of rectangle = 14 m

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