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butalik [34]
3 years ago
6

Consider the table for the exponential function, LaTeX: p\left(x\right)=2^xp ( x ) = 2 x, shown below. Calculate the Average Rat

e of Change between the interval [2, 6].

Mathematics
1 answer:
Mice21 [21]3 years ago
3 0

Answer:

15

Step-by-step explanation:

To find the average rate if change of the exponential function between the interval [2, 6], use the formula, m = \frac{p(b) - p(a)}{b - a}

Where,

a = 2, p(2) = 4

b = 6, p(6) = 64

Plug in the above values into the formula:

m = \frac{64 - 4}{6 - 2}

m = \frac{60}{4}

m = 15

Average rate of change is 15

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2x2– 21x = 11 what would the x be
Gnom [1K]

Answer:

x = -1/3

Step-by-step explanation:

7 0
3 years ago
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What is the area of a trapezoid that has a bases measuring 19 cm and 23 cm, and a height of 14 cm?
kramer

s =  \frac{a + b}{2}  \times h

S = (19+23)/2×14

S = 42/2×14

S = 21×14

S = 294 cm^2

6 0
4 years ago
When it is operating properly, a chemical plant has a daily production rate that is normally distributed with a mean of 885 tons
-BARSIC- [3]

Answer:

<em>The test statistic Z = 1.844 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<em>Yes he is right</em>

<em>The manager claims that at least 95 % probability that the plant is operating properly</em>

Step-by-step explanation:

<u>Explanation</u>:-

Given data Population mean

                                           μ     = 885 tons /day

Given random sample size

                                          n = 60

mean of the sample

                                        x⁻  = 875 tons/day

The standard deviation of the Population

                                      σ = 42 tons/day

<em><u>Null hypothesis</u></em><em>:- H₀: </em>The manager claims that at least 95 % probability that the plant is operating properly

<u><em>Alternative Hypothesis :H₁</em></u>: The manager do not claims that at least 95 % probability that the plant is operating properly

<em>Level of significance</em> =  0.05

The test statistic

 Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

Z = \frac{875 -885}{\frac{42}{\sqrt{60} } }

Z = \frac{-10}{5.422} = -1.844

|Z| = |-1.844| = 1.844

<em>The tabulated value</em>

<em>                          </em>Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96<em></em>

<em>The calculated value Z = 1.844 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<u><em>Conclusion</em></u><em>:-</em>

<em>The manager claims that at least 95 % probability that the plant is operating properly</em>

<em></em>

<em></em>

8 0
3 years ago
MS. Kitts works at a music store. Last week she sold 6 more than 3 times the number of CDs that she sold this week. Ms. Kitts so
puteri [66]

x - 3y = 6 and x + y = 110 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week

number of CDs Kitts sold last week "x" is 84 and number of CDs she sold this week "y" is 26

<h3><u>Solution:</u></h3>

Let "x" be the number of CDs Kitts sold last week

Let "y" be the number of CDs she sold this week

<em><u>Given that Last week she sold 6 more than 3 times the number of CDs that she sold this week</u></em>

Number of CDs Kitts sold last week = 6 + 3(number of CDs that she sold this week)

x = 6 + 3y ----- eqn 1

x - 3y = 6 ------- eqn 2

<em><u>Given that Ms. Kitts sold a total of 110 CDs over the 2 weeks</u></em>

Number of CDs Kitts sold last week + number of CDs she sold this week = 110

x + y = 110 ----- eqn 3

Thus eqn 2 and eqn 3 represents the system of equations used to find x, the number of CDs she sold last week, and y, the number of CDs she sold this week

<em><u>Let us solve the above equations to find values of "x" and "y"</u></em>

Substitute eqn 1 in eqn 3

6 + 3y + y = 110

6 + 4y = 110

4y = 104

<h3>y = 26</h3>

From eqn 3,

x + 26 = 110

x = 110 - 26 = 84

<h3>x = 84</h3>

Thus number of CDs Kitts sold last week = x = 84

Number of CDs she sold this week = y = 26

6 0
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Answer:

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