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daser333 [38]
3 years ago
8

Which statement BEST explains the relationship among these three facts?

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0

Answer:

The chocolate drink became popular in Europe, because sugar made it taste better.

Hope this helps! :)

nikitadnepr [17]3 years ago
5 0

Answer:

<h2>The chocolate drink became popular in Europe because sugar made it taste better.</h2>

Step-by-step explanation:

According to the problem, we have the following premises:

  • Natural chocolate taste bitter.
  • The Spanish began adding sugar to chocolate water.
  • Chocolate houses appeared throughout Europe.

From this premises, we can deduct that once The Spanish added sugar to the chocolate, it became popular and Chocolate houses appeared to sell this product. But, only after adding sugar, because before it, people don't like it, because natural chocolate doesn't taste good.

Therefore, the right conclusion among the options would be:

<em>The chocolate drink became popular in Europe because sugar made it taste better.</em>

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Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls
murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4})  + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4})  + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222

Hence,

P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684

Part b

P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}

Hence,

P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}

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