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Liono4ka [1.6K]
3 years ago
14

PLEASE SOMEONE HELP ME I WILL DO ANYTHING FOR YOU!!!!!!!!!!!!

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:


Step-by-step explanation:

It is 38

Vadim26 [7]3 years ago
8 0

Answer:

40

Step-by-step explanation:

Not 100% sure if this is right way, but I know right answer.

Third quartile is number between median and highest value.

Median = 33

Highest = 46

46 - 33 = 13

13 / 2 = 6.5

33 + 6.5 = 39.5, round to 40.

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Can you help me with this
Karo-lina-s [1.5K]

Answer

38°

Step-by-step explanation:

52+90+x=180

180-52-90=x

x=38

3 0
2 years ago
Read 2 more answers
If rhe discriminant of a quadratic equation is equal to -8 which statement describes the roots
Nastasia [14]

Answer:

Step-by-step explanation:

Given

Discriminant = -8

Required

Determine the type of roots

Represent Discriminant with D; such that

D = -8

D is calculated as thus

D = b^2 - 4ac

And it has the following sequence of results

When D > 0; then the roots of the quadratic equation are real but not equal

When D = 0; then the roots of the quadratic equation are real and equal

When D < 0; then the roots of the quadratic equation are complex or imaginary

Given that D = -8; This means that D < 0; and base on the above analysis, we can conclude that the roots of the quadratic equation are complex or imaginary

6 0
3 years ago
Please please please help!
lys-0071 [83]

Answer:

6 pounds

Step-by-step explanation:

every 16 ounces =1 pound

so 96/16 = 6

6 *1 = 6

therefour 6 pounds

4 0
3 years ago
The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte
Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

[(n - 1)\times S^{2}  /  X^{2}  \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2}  / X^{2} 1- \alpha/2, n- 1 ]

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

X^{2}_{[\alpha/2, n - 1]}   = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0
2 years ago
What are the outliers???
Marina86 [1]
There’s no image to show the outliers
7 0
2 years ago
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