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just olya [345]
3 years ago
10

In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

iation of 5.4 minutes. It is assumed that this is a normally distributed variable.
Find the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

a)0.38

b)0.69

c)0.99

d)0.31
Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer: d) 0.31

Step-by-step explanation:

Given : In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes.

i.e. \mu=42.5 and \sigma= 5.4

It is assumed that this is a normally distributed variable.

Let x denotes the time spend by a person on treadmill.

Then, the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

P(30

Hence, the required probability = 0.31

Thus , the correct answer = d) 0.31

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The cube root of the difference of a number and 2
julia-pushkina [17]

Answer:

The difference of two cubes is equal to the difference of their cube roots times a trinomial, which contains the squares of the cube roots and the opposite of the product of the cube roots. A number's opposite is that same number with a different sign in front.

Step-by-step explanation:

8 0
3 years ago
A Statistics professor has observed that for several years students score an average of 106 points out of 150 on the semester ex
tekilochka [14]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 106

For the alternative hypothesis,

µ > 106

It is a right tailed test because of >.

Since no population standard deviation is given, the distribution is a student's t.

Since n = 241,

Degrees of freedom, df = n - 1 = 241 - 1 = 240

t = (x - µ)/(s/√n)

Where

x = sample mean = 109

µ = population mean = 106

s = samples standard deviation = 8.3

a) test statistic, t = (109 - 106)/(8.3/√241) = 5.61

We would determine the p value using the t test calculator. It becomes

p = 0.00001

Since alpha, 0.05 > than the p value, 0.00001, then we would reject the null hypothesis. Therefore, At a 5% level of significance, this improvement seem to be practically​significant.

b) Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

n = number of samples

From the information given, the population standard deviation is unknown, hence, we would use the t distribution to find the z score

df = 240

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 1.6512

Margin of error = 1.6512 × 8.3/√241

= 0.88

Confidence interval = 109 ± 0.88

7 0
3 years ago
If I can paint 96 sq ft in 15 minutes how long does it take to paint 1 sq ft
White raven [17]

It takes 0.15625 minutes to paint 1 square feet

<em><u>Solution:</u></em>

Given that, I can paint 96 sq ft in 15 minutes

To find: Time taken to paint 1 square feet

From given,

96 square feet is painted in 15 minutes

Let "x" be the time taken to paint 1 square feet

Then, we can say,

96 square feet = 15 minutes

1 square feet = x minutes

This forms a proportion and we can solve the sum by cross multiplying

96 \times x = 15 \times 1\\\\x = \frac{15}{96}\\\\x = 0.15625

Thus it takes 0.15625 minutes to paint 1 square feet

8 0
3 years ago
The stem-and-leaf plot shows the scores of a class of sixth graders on a math test.
SOVA2 [1]

A stem and leaf plot shows sets of two digit numbers, by separating the ten’s place and the one’s place. On the left is the different ten’s values, while on the right next to each of the values on the left is the one’s values that associate with each of the ten’s values. This means that the numbers in this set of data are 32, 47, 51, 55, 55, 55, 58, 64, and so on. From there, you can use that knowledge to figure out how many scores were above 60.


The terms that are above 60 are 64, 65, 73, 74, 77, 87, 88, 91, 93, 93, 97, 99, and 99, for a total of 13 of the 20 scores being above 60.

8 0
3 years ago
A group of friends were working on a student film that had a budget of $900. They used 79% of their budget on equipment. How muc
Mariana [72]

Answer:

711

Step-by-step explanation:

They used 79/100 of their money on equipment which means if they have a budget of 900 dollars they used...

900*79/100=9*79=711 dollars on equipment.

8 0
3 years ago
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