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just olya [345]
3 years ago
10

In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard dev

iation of 5.4 minutes. It is assumed that this is a normally distributed variable.
Find the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

a)0.38

b)0.69

c)0.99

d)0.31
Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer: d) 0.31

Step-by-step explanation:

Given : In a health club, research shows that on average, patrons spend an average of 42.5 minutes on the treadmill, with a standard deviation of 5.4 minutes.

i.e. \mu=42.5 and \sigma= 5.4

It is assumed that this is a normally distributed variable.

Let x denotes the time spend by a person on treadmill.

Then, the probability that randomly selected individual would spent between 30 and 40 minutes on the treadmill.

P(30

Hence, the required probability = 0.31

Thus , the correct answer = d) 0.31

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