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Semmy [17]
3 years ago
12

What short (two letters!) but powerful boolean operator can check whether or not one string can be found in another string?

Computers and Technology
1 answer:
True [87]3 years ago
4 0

Answer:

OR

Explanation:

"OR" expands a search by telling the database that any of the words it connects are acceptable. This is particularly beneficial when you are searching for synonyms, such as “the victorian age” OR “sexual puritanism”  

So, if you type in “the victorian age” OR “sexual puritanism”, your results will include articles with either term, but not necessarily both.

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1. Why does a computer have different types of ports?
iren2701 [21]

Answer:

Computer ports are classified into two types based on the protocols used. A protocol is a set of rules and standards to be followed during data transfer and communication. Usually, data is transmitted in a particular pattern.

Explanation:

3 0
2 years ago
Read 2 more answers
Tortise and hare race java g Modify the main class so it runs the race 100 times and reports how many times each runner wins. (T
SOVA2 [1]

Answer:

Game.java file

import java.util.Scanner;

public class Game {

/**

* t_pos and h_pos are the current positions of the Tortoise and Hare

*/

static int t_pos,h_pos;

static Tortoise tortoise;

static Hare hare;

public static void main(String[] args) {

play(); /*starting the game*/

}

public static void play(){

/**

* the method will starts the play, loop until the game is over, displays the winner

* and prompts the user if they want to play again

*/

/**

* defining Tortoise and Hare objects

*/

tortoise=new Tortoise();

hare=new Hare();

t_pos=1;

h_pos=1;

System.out.println("The race is about to start");

tortoise.printTrack();

hare.printTrack();

while(t_pos != 50 && h_pos !=50){

System.out.println("\n\n\n"); /*printing blank lines*/

t_pos=tortoise.move(); /*moving and getting the current position of tortoise*/

h_pos=hare.move();/*moving and getting the current position of hare*/

tortoise.printTrack(); /*displaying the tracks*/

hare.printTrack();

try { /*comment this part to skip the 1s break between each round; for testing*/

Thread.sleep(1000);

} catch (InterruptedException e) {

e.printStackTrace();

}

}

System.out.println("\nRace Over");

if(t_pos==50 && h_pos==50){

System.out.println("Its a tie");

}

else if(t_pos==50){

System.out.println("Tortoise wins");

}else if(h_pos==50){

System.out.println("Hare wins");

}

System.out.println("Do you want to play again? (y/n)");

Scanner scanner=new Scanner(System.in);

String ch=scanner.next();

if(ch.equalsIgnoreCase("y")){

play();

}else if(ch.equalsIgnoreCase("n")){

System.out.println("Thanks for playing, Goodbye");

}else{

System.out.println("Invalid choice, quitting..");

}

}

}

//Tortoise.java

public class Tortoise {

/**

* the current position of the tortoise

*/

int position;

/**

* track array

*/

char[] track;

/**

* speed of tortoise

*/

int speed=1;

public Tortoise() {

position=0;

track=new char[50];

for(int i=0;i<track.length;i++){

/**

* filling the track

*/

track[i]='-';

}

}

public int move(){

if(position<track.length){

position=position+speed;

}

return position+1;

}

public void printTrack(){

/**

* the current position of tortoise will be displayed by 'T' everything else will be '-'

*/

System.out.println();

for(int i=0;i<track.length;i++){

if(i==position){

System.out.print('T');

}else{

System.out.print(track[i]);

}

}

}

}

//Hare.java

import java.util.Random;

public class Hare {

int position;

int speed=10;

char[] track;

/**

* Random object to generate a random number

*/

Random random;

/**

* resting percent denotes how much time Hare will be resting

*/

int resting_percent=90;

public Hare() {

position=0;

track=new char[50];

for(int i=0;i<track.length;i++){

track[i]='-';

}

random=new Random();

}

public int move(){

int n=random.nextInt(100-1)+1; /*generating a random number between 1 and 100*/

if(n<=resting_percent){

/**

* at rest; will not move, returns the current position.

*/

return position;

}else{

/**

* not resting..

*/

if(position<track.length){

if(position+speed>=track.length){

position=track.length-1;

}else{

position=position+speed;

}

}

return position+1;

}

}

public void printTrack(){

System.out.println();

for(int i=0;i<track.length;i++){

if(i==position){

System.out.print('H');

}else{

System.out.print(track[i]);

}

}

}

}

/*Output (partial and random)*/

The race is about to start

T-------------------------------------------------

H-------------------------------------------------

-T------------------------------------------------

H-------------------------------------------------

--T-----------------------------------------------

H-------------------------------------------------

---T----------------------------------------------

----------H---------------------------------------

.

.

.

.

-----------------------------------------------T--

-------------------------------------------------H

Race Over

Hare wins

Do you want to play again? (y/n)

y

The race is about to start

T-------------------------------------------------

H-------------------------------------------------

-T------------------------------------------------

H-------------------------------------------------

.

.

.

.

-----------------------------------------------T--

--------------------H-----------------------------

------------------------------------------------T-

--------------------H-----------------------------

-------------------------------------------------T

--------------------H-----------------------------

Race Over

Tortoise wins

Do you want to play again? (y/n)

n

Explanation:

3 0
3 years ago
In basic network scanning, ICMP Echo Requests (type 8) are sent to host computers from the attacker, who waits for which type of
Hoochie [10]

Answer:

d. ICMP Echo Reply (type 0)

Explanation:

ICMP or internet control message protocol is an Internet layer protocol in the TCP/IP suite. It works together with routing devices like the router to send messages based on results sensed in the network.

The RFC 1122 has stated that the ICMP server and end user application be configured or installed in user devices, for receiving and sending ICMP echo request packets and reply. The process is called pinging.

For an attacker to implement ping of ping, he needs to confirm if the target user in live by sending an ICMP echo request packet type 8, to receive an ICMP echo reply type0.

4 0
3 years ago
NumA=2<br> for count range (5,8)<br> numA=numA+count <br> print(numA)
love history [14]

Answer:

for count in range (5,8): numA=numA+count print(numA)

Explanation:

7 0
3 years ago
7.12 LAB: Even/odd values in a list
Korvikt [17]

The odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is zero (0).

<h3>What are even numbers and odd numbers?</h3>

The even numbers can be found in a list because they are divisible by two and the remainder of this equation is always zero (0).

Conversely, odd numbers are those that cannot be divided exactly into exact entire numbers (e.g., 3, 5, etc).

The odd numbers in a list can be calculated by the equation ON (odd numbers): n/2 × [f + g], where 'f' is the first number and 'g' is the last number.

In conclusion, the odd values in a list can be calculated by knowing the first and last number, whereas even numbers can be divided by two and the remainder is 0.

Learn more about odd numbers here:

brainly.com/question/2263958

#SPJ1

4 0
2 years ago
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