The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height
The given expression for the area, 81x² - 4y², is a difference of two squares. The first term is the square of 9x and the second term is the square of 2y. The factors of this difference and the therefore the dimensions of the rectangle are, 9x - 2y and 9x + 2y.
93 * 20 / 120 = 15.5
<span>a 93-pound person weighs on the Earth will weigh 15.5 lbs on Moon</span>
Answer:
on the y axis
Step-by-step explanation:
