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Allushta [10]
3 years ago
6

Maggie's brother is 3 years younger than twice her age. The sum of their ages is 12.

Mathematics
1 answer:
Lilit [14]3 years ago
3 0
I’d say 21 tbh unless the sum is half of the brothers age then it would be 9
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8x+12-8x+15+15x-22-x
mixas84 [53]
The answer would be 14x+5 I’m pretty sure
5 0
3 years ago
Find the missing side or angle. Round to the nearest tenth. C=53° B= 80° a=2 b=[ ? ]​
Degger [83]

9514 1404 393

Answer:

  b ≈ 2.7

Step-by-step explanation:

The missing angle A is ...

  A = 180° -53° -80° = 47°

The law of sines tells you ...

  b/sin(B) = a/sin(A)

  b = sin(80°)×2/sin(47°) ≈ 2.6931

Side b is about 2.7 units.

5 0
3 years ago
Read 2 more answers
A department store buys 300 shirts at a cost of ​$2,100 and sells them at a selling price of ​$10 each. Find the percent markup
denis23 [38]

Answer:

markup 3 dollars a shirt. Total markup 900$

Step-by-step explanation:

4 0
3 years ago
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Two welders worked a total of 46 h on a project. One welder made $34/h, while the other made $39/h. If the gross earnings of the
Ratling [72]

Answer:

25 and 21 hours respectively

Step-by-step explanation:

Let the number of hours worked by each welder be x and y respectively.

They worked a total of 46 hours. This means :

x + y = 46 hours.......(I)

Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:

34x + 39y = 1669........(ii)

We then solve both simultaneously. From I, x = 46 -y

We can substitute this into ii

34(46 -y) + 39y = 1669

1564 -34y + 39y = 1669

5y = 1669 - 1564

5y = 105

y = 105/5 = 21

x = 46 - y

x = 46 - 21 = 25 hours

The numbers of hours worked by the welders are 25 and 21 respectively

4 0
3 years ago
Someone help me with this one​
frosja888 [35]

Answer:

2/3

Step-by-step explanation:

20% = 12

48

1/6 = 8

left = 40

40/60 = 4/6

4/6 = 2/3

3 0
4 years ago
Read 2 more answers
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