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3 years ago

Maggie's brother is 3 years younger than twice her age. The sum of their ages is 12.

Mathematics

1 answer:

Lilit [14]3 years ago

3 0

I’d say 21 tbh unless the sum is half of the brothers age then it would be 9

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The cost price of a box and a pen is Rs 120. The box is sold at 10% profita the pen is sold at 10% loss. If the selling price of

matrenka [14]

Answer:

3.803% Profit

Step-by-step explanation:

First let us calculate total sales, then calculate the total cost, and then divide the two.

Sale: 120*1.1=132 and 52*.9=46.8

Cost: 120 and 52

Profit equation:

$\frac{Net sales-COGS}{Net Sales} =Profit$

$\frac{(132+46.8)-(120+52)}{(132+46.8)}$

Simplify:

$\frac{6.8}{178.8} =.03803$ or 3.803% Profit

5 0

3 years ago

Answer Please this is really important

trapecia [35]

Answer:

B) Parallel

Step-by-step explanation:

The lines have the same slope of $\frac{4}{3}$ . This makes the lines parallel.

Hope it helps!

3 0

3 years ago

Read 2 more answers

The table shows the price for shoe rental, games, and snacks at the bowling alley

monitta

First, find the total price she would have had to pay (without tax):
2.75+ 3(2.5)+ 1.75=12
If she has half-price multiply the total price by 0.5:
12(.5)=6
Her total price without tax is $6.

The answer is B) $6.00
Hope I helped...

6 0

4 years ago

Helppppppppppppppp plsssssssssss

mel-nik [20]

Answer:

y=5/1 - 3

Step-by-step explanation:

use rise over run

8 0

2 years ago

Find the area of the shaded region.

lbvjy [14]

Answer:

$48\pi\\\approx 150.796$

Step-by-step explanation:

1.Approach

To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.

2.Find the area of the larger circle

The formula to find the area of a circle is the following,

$A=(\pi)(r^2)$

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. ( $\pi$ ) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

$A_l=(\pi)(r^2)\\A_l=(\pi)(8^2)\\A_l=(\pi)(64)$

3.Find the area of the smaller circle

To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.

8 ÷2 = 4

Radius = 4

Substitute into the formula,

$A_s=(\pi)(r^2)\\A_s=(\pi)(4^2)\\A_s=(\pi)(16)$

4.Find the area of the shaded region

Subtract the area of the smaller circle from the area of the larger circle.

$A_l-A_s\\=64\pi - 16\pi\\=48\pi$

$\approx150.796$

5 0

3 years ago