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3 years ago

Find three consecutive integers such that three times The largest increased by two is equal to five times the smallest increased

by three times the middle integer

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

$a,a+1,a+2-\ three\ consecutve\ integers\\\\
3*(a+2)+2=5*(a+3)+3(a+1)\\\\
3a+6+2=5a+15+3a+3\\\\
3a+8=8a+18\ \ \ | subtract\ 3a\\\\
8=5a+18\ \ \ \ | subtract\ 18\\\\
-10=5a\ \ \ \ | divide\ by\ 5\\\\
a=-2\\\\Numbers\ are:\ \ -2,-1,0
$

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2 years ago

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3 years ago

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Step-by-step explanation:

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3 years ago

the diffrence of two numbers,a and b,is 21,the diffrence of five times a and two times b is 18 what are the values of a and b

Triss [41]

Answer:

a=-8

b=-29

Step-by-step explanation:

Let's assume

first number is a

second number is b

the difference of two numbers,a and b,is 21

so, we get

$a-b=21$

we can solve for 'a'

$a=b+21$

the difference of five times a and two times b is 18

so, we get

$5a-2b=18$

now, we can plug 'a'

$5(b+21)-2b=18$

now, we can solve for b

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$3b+105=18$

$3b=-87$

$b=-29$

now, we can find 'a'

$a=-29+21$

$a=-8$

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