Question

Find three consecutive integers such that three times The largest increased by two is equal to five times the smallest increased by three times the middle integer

Answer 1

$a,a+1,a+2-\ three\ consecutve\ integers\\\\ 3*(a+2)+2=5*(a+3)+3(a+1)\\\\ 3a+6+2=5a+15+3a+3\\\\ 3a+8=8a+18\ \ \ | subtract\ 3a\\\\ 8=5a+18\ \ \ \ | subtract\ 18\\\\ -10=5a\ \ \ \ | divide\ by\ 5\\\\ a=-2\\\\Numbers\ are:\ \ -2,-1,0$