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3 years ago

Given: g(x) = /x-4 and h(x) = 2x-8

Mathematics

2 answers:

Lelu [443]3 years ago

7 0

Answer:

I think its x not = 4 because that would make the denominator = 0 after the multiplication. (g x h = 2x - 8 / x - 4

Step-by-step explanation:

soldi70 [24.7K]3 years ago

5 0

Answer:6

Step-by-step explanation:

You might be interested in

100 POINTS! NEED HELP QUICKLY! Look at picture below

Delvig [45]

Answer:

60, 75

150 165

240 255

330 345

Step-by-step explanation:

csc 4 theta = -2 sqrt(3)/3

Write in terms of sin

1/ sin (4 theta) = -2 sqrt(3)/3

Using cross products

-2 sqrt(3) = 3 sin (4 theta)

Divide each side by 3

-2 sqrt(3)/3 = sin (4 theta)

Take the inverse sin on each side

sin ^ -1(-2 sqrt(3)/3) = sin ^ -1 (sin (4 theta))

240 +360n = 4 theta

and 300 +360n = 4 theta where n is an integer

Dividing each side by 4

240/4 +360n/4 = 4/4 theta and 300/4 +360n/4 = 4/4 theta

60 + 90n = theta and 75 +90n = theta

We want all the values between 0 and 360

Let n=0

60, 75

n=1

60+90=150 and 75+90 =165

n=2

60+180= 240 75+180=255

n=3

60+270 = 330 75+ 270 =345

7 0

3 years ago

3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo

salantis [7]

Answer:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: