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Yuliya22 [10]
3 years ago
7

Given: g(x) = /x-4 and h(x) = 2x-8

Mathematics
2 answers:
Lelu [443]3 years ago
7 0

Answer:

I think its x not = 4 because that would make the denominator = 0 after the multiplication. (g x h  =  2x - 8 / x - 4

Step-by-step explanation:


soldi70 [24.7K]3 years ago
5 0

Answer:6

Step-by-step explanation:

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konstantin123 [22]

Answer:

b)\ 0.568

Step-by-step explanation:

Given

f(x) = 6x(1- x);\ 0 \le x \le 1

Required

P(0.3 < x < 0.7)

From the question, we have:

P(a < x < b) = \int\limits^b_a {f(x)} \, dx

So, we have:

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx

Open bracket

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx

Integrate

P(0.3 < x < 0.7) =  \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}

P(0.3 < x < 0.7) =  3x^2 - 2x^3|\limits^{0.7}_{0.3}

Substitute 0.7 and 0.3 for x

P(0.3 < x < 0.7) =  (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)

Using a calculator, we have:

P(0.3 < x < 0.7) =  (0.784) - (0.216)

Remove brackets

P(0.3 < x < 0.7) =  0.784 - 0.216

P(0.3 < x < 0.7) =  0.568

3 0
2 years ago
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