Answer: can’t answer without a picture or the problem
Step-by-step explanation:
Rather than trying to guess and check, we can actually construct a counterexample to the statement.
So, what is an irrational number? The prefix "ir" means not, so we can say that an irrational number is something that's not a rational number, right? Since we know a rational number is a ratio between two integers, we can conclude an irrational number is a number that's not a ratio of two integers. So, an easy way to show that not all square roots are irrational would be to square a rational number then take the square root of it. Let's use three halves for our example:

So clearly 9/4 is a counterexample to the statement. We can also say something stronger: All squared rational numbers are not irrational number when rooted. How would we prove this? Well, let
be a rational number. That would mean,
, would be a/b squared. Taking the square root of it yields:

So our stronger statement is proven, and we know that the original claim is decisively false.
Step-by-step explanation:
= 0,4 ÷ 29,5
= (0,4 × 10) ÷ (29,5 × 10)
= 4 ÷ 295
= 4/295
The answer is: " 53
% " .
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→ " 53
% " of 75 is "40" .
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Explanation:
To solve:
* 75 = 40 ;
→ Rewrite as:
*
= 40 ;
→ The "100" cancels to "4" ; and the "75" cancels to "3" ;
→ {since: "{100 ÷ 25 = 4}" ; and since: "{75 ÷ 25 = 3"} ;
→ So; we rewrite the problem as:
→
*
= 40 ;
→ which is:
* 3 = 40 ;
→ Divide each side of the equation by "3" ;
* 3 ÷ 3 = 40 ÷ 3 ;
to get:
→
=
;
Now, cross-multiply:
→ 3x = (4)*(40) ;
→ 3x = 160 ;
Divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 160 / 3 ;
to get:
→ x = 53
.
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These equations do match up. All you have to do is find the solution to the first equation. After that, plug in that solution to the second equation. If it makes the equation true, then the equations match.
Hope this helps!