Answer:
2p-1/p
Step-by-step explanation:
Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other
Given the functions expressed as:

In order to check whether they are inverses of each other, we need to show that h(g(x)) = g(h(x))
Get the composite function h(g(x))

Get the composite function g(h(x))

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other
Learn more on inverse functions here; brainly.com/question/14391067
Answer:
0.31
Step-by-step explanation:
So if you divide 31 by 100 all you have to do is move the decimal from right to left the number of zeros you have. Here we have 2 zeros so we move from right to left twice.
0.31
For this case we have the following function transformation:
Vertical displacement.
Assume k> 0
If f (x) is the original function, f (x) + k is the original function with a vertical displacement k units up.
Answer:
Part 1:
C. The function is not shifted horizontally from g (x)
Part 2:
A. 3 units up from g (x)
Answer:
Step-by-step explanation:
The difference of two squares may be represented by the formula: a^2-b^2,
which can be factored as (a+b)(a-b)
A perfect square trinomial may be represented by the formula: a^(2)-2ab+b^2 or a^(2)+2ab+b^2, depending on the sign of b
if b is negative: use the formula a^(2)-2ab+b^2, which can be factored as (a-b)*(a-b) or (a-b)^(2)
if b is positive: use the formula a^(2)+2ab+b^2, which can be factored as (a+b)*(a+b) or (a+b)^(2)