First, we need to know how much the car depreciates each year. Multiply the price of the car by the percentage.
We can turn 9% into a decimal by moving the decimal point two places to the right.
9% = .09
24500 * .09 = 2205
Multiply the product by the amount of years you want to predict the price at.
2205 * 10 = 22050
Subtract that from the original price of the car.
24500 - 22050 = 2450
The value of a 10 year old car that costs $24500 and depreciates 9% every year will cost $2450.
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
- Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
- Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
- Finally we add up the following shapes Volume which are 6160+420=6580cm
x/110 = (320-x)/90
<span> Cross multiply</span>
90x = 35200-110x
200x=35200
X = 35200/200 = 176 (distance traveled by train going 110 mph
176/110 = 1.6 hours = 1 hour and 36 minutes
Check: 110*1.6 = 176, 90*1.6 = 144
176+144 = 320
it will take 1.6 hours ( 1 hour 36 minutes) for the trains to meet
If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
