Answer:
it's c
Step-by-step explanation:
Answer:
Step-by-step explanation:
A person invested $2,500 in an account growing at a rate allowing the money to double every 11 years. How long, to the nearest tenth of a year would it take for the
value of the account to reach $3,800?
The formula for exponential growth given as:
A(t) = Ao (1/2)^t/t½
A(t) = Amount after time t = $3,800
Ao = Initial amount invested = $2500
t = Time in years
t½ = Time it takes to double = 11 years
Hence,
3800 = 2500(1/2)^t/11
Divide both sides by 2500
3800/2500 = 2500(1/2)^t/11/2500
The general equation with quadratic equation is “ax^2 + bx + c = 0”. Therefore, this equation can be standardized to “x^2 - 7x - 8 = 0”
If T is the midpoint, then that means its exactly 1/2 of the way between 2 points
this means we can set the 2 given values equal
4x - 3 = 2x + 7
first move like terms to the same side
2x = 10
x = 5
now that we know the length of x, we plug it back in to get the length
4x - 3 + 2x + 7 = 6x + 4
6(5) + 4 = 34
