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3 years ago

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Twice the sum of two numbers is 24. if one number is 2 times larger than the other, what is the smaller of the two numbers?

1 answer:

Vikki [24]3 years ago

4 0

2(x+y)=24
2x=y

Use substitution. If y=2x, than we can substitute 2x for it in the other equation, because x and y equal the same things in both equations.

So using that we get 2(x+2x)=24

SIMPLIFY
2(3x)=24

DISTRIBUTE
6x=24.

DIVIDE: x=4.

If we substitute x into the original equations we get x=4 and y=8. Those are your two numbers.

Have a nice day! :)

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Read 2 more answers

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$\vec F(x,y,z)=(e^x+y)(1,1,z)$

is conservative if we can find a scalar function $f$ such that $\nabla f=\vec F$ . This would require

$f_x=e^x+y$

$f_y=e^x+y$

$f_z=(e^x+y)z$

Integrating both sides of the first equation wrt $x$ gives

$f(x,y,z)=e^x+xy+g(y,z)$

Differentiating both sides of this wrt $y$ gives

$f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)$

but we assumed $g$ was a function of $y$ and $z$ , independent of $x$ . So there is no such $f$ and $\vec F$ is not conservative.

To find the work, first parameterize the path (call it $C$ ) by

$\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)$

for $0\le t\le1$ . Then

$\vec r'(t)=(-4,5,-5)$

and the work is given by the line integral,

$W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt$

$W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}$

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