10 ( 4 + 6b ) - 28b + 23? PLSSS HELPPP MEEE

1. what is the GCF of the terms of 8c^3+12c^2+10c?

STatiana [176]

If you pay attention 2 goes into 8, 10, & 12 and it looks like they all have one C. So what do you think it is lol?(:

8 0

3 years ago

Read 2 more answers

PLEASE HELP IM TIMED!! WILL GIVE BRAINLEST!!

Goshia [24]

Answer:

The answer is C

Step-by-step explanation:

An isosceles triangle has two angles that measure the same, so...

30 + 30 = 60

180 - 60 = 120

No

____________

45 + 45 = 90

180 - 90 = 90

No

____________

60 + 60 = 120

180 - 120 = 60

Yes

____________

90 + 90 = 180

No

5 0

3 years ago

Let the equation C= 2.32 N + 34,180 represent the cost of raising a child, C on an income, N. If the Corlone family has an incom

Genrish500 [490]

Answer:

$126,980

Step-by-step explanation:

Given the equation C = 2.32N + 34,180 where 'C' is the cost of raising a child and 'N' is the income. If the Corlone family has an income of $40,000, you can use this value for 'N' and solve for 'C':

C = 2.32(40,000) + 34,180

C = 92,800 + 34,180

C = $126,980

8 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$