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2 years ago

5

Bree took a math test and scored 19 points, which was 95% of the total possible points on the test. What was the total number of

possible points

1 answer:

NISA [10]2 years ago

3 0

Answer: 20 points hope this helps

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Plz help me, no one has. I'll give 100 brainly pts

Serhud [2]

Answer:

to find the distance between two points, in order to find the length of the triangle we need first to find the instance between the two points

distance between (2,9) and (2,4) .....a =5

distance between (2,4) and (6,4) .....b = 4

when we find the length of the side of the triangle , then we can apply the Pythagorean theorem to find hyp. c

a²+b²=c²

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2 years ago

Write an expression that is equivalent to (3+14)+27

Julli [10]

Answer:

44

Step-by-step explanation:

1. (3+14)=17

2. 17 + 27= 44

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3 years ago

The missing exponent for 1/169?

enot [183]

The missing exponent of 1/169=(1/13)

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3 years ago

Stewart has a home-based business putting on children’s parties. He charges $60 to design the party and then $6.00 per child. Wr

Aleksandr [31]

Answer:

<h2>f(n) = 60 + 6n</h2>

Step-by-step explanation:

numbers of students = n

party decoration charge = 60

per child cost = 6

so, therefore

f(n) = 60 + 6n

<h2 /><h2>MARK ME AS BRAINLIST</h2><h3>PLZ FOLLOW ME</h3>

7 0

2 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM . AC:CM=3:4, MP-AP=1. Find AM.

lana [24]

Answer:

$AM=\frac{25}{7}$

Step-by-step explanation:

It is given that AC:CM = 3:4.

Therefore, let AC = 3k and CM = 4k

It is given that Δ ACM is right angled.

Therefore,

$AM^{2} =AC^{2} +CM^{2}$

$=(3k)^{2} +(4k)^{2}$

$=9k^{2} +16k^{2}$

$=25k^{2}$

AM = 5k

But, AM = MP + AP

Therefore, MP + AP = 5k --- (1)

It is given that MP - AP = 1 --- (2)

Multiply (1) and (2), we get.

(MP + AP)(MP - AP) = 5k × 1 = 5k

$MP^{2} -AP^{2} =5k$

Add and subtract $CP^{2}$ on the left side.

$MP^{2} + CP^{2} - CP^{2} -AP^{2} =5k$

$(MP^{2} + CP^{2}) - (CP^{2} +AP^{2}) =5k$ --- (3)

But, since CP ⊥ AM, Δ CMP and Δ CAP are right triangles. Therefore,

$MP^{2} +CP^{2} =CM^{2}$ and

$CP^{2} +AP^{2} =AC^{2}$

Now, (3) becomes,

$CM^{2} -AC^{2} =5k$

$(4k)^{2} -(3k)^{2} =5k$

$7k^{2} =5k$

7k = 5 or

$k=\frac{5}{7}$

AM = 5k

$=5(\frac{5}{7} )$

$=\frac{25}{7}$

6 0

2 years ago