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puteri [66]
4 years ago
7

The equilibrium-constant expression depends on the of the reaction. (A) stoichiometry (B) mechanism (C) stoichiometry and mechan

ism (D) the quantities of reactions and products initially present (E) temperature
Chemistry
1 answer:
myrzilka [38]4 years ago
8 0

Answer:

(A) stoichiometry

Explanation:

For example, Consider the reaction of the type ,

aA + bB-----> cC +dD

where b, a, d, and c are the stoichiometric coefficients for the balanced equation .

The equilibrium constant expression is denoted by K ,

equilibrium constant is the product's concentration each raised to the power of its corresponding stoichiometries , divided by reactant's concentration each raised to the power of its corresponding stoichiometries .

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gogolik [260]
They are identical to the nucleus of the helium-4 atom. So the answer is helium atoms.

Hope this helps! :)
4 0
4 years ago
How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?
tino4ka555 [31]

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO₂: 1 mole
  • H₄: 4 moles  
  • CH₄: 1 mole
  • H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}

<u><em>moles of CH₄= 340.4 moles</em></u>

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

6 0
2 years ago
If a reaction mixture contains only N2O and NO2 at partial pressures of 1.0 atm each, the reaction will be spontaneous until som
Vesna [10]

Answer:

Temperature required = 923K

Explanation:

The question is incomplete as there are some details that has to be given. details like the values of the standard enthalpies and entropies of the reactants and product as this is needed to calculate the actual value of the standard enthalpies and standard entropies of the reaction. I was able to get those values from literature and then calculated what needs to be calculated.

From there, I was able to use the equation that shows the relationship between, gibb's free energy, enthalpy, entropy and temperature. The necessary mathematical manipulation were done and the values were plugged in to get the temperature required to make the reaction spontaneous.

A few notes on the Gibb's free energy.

The Gibb's free energy also referred to as the gibb's function represented with letter G. it is the amount of useful work obtained from a system at constant temperature and pressure. The standard gibb's free energy on the other hand is a state function represented as Delta-G, as it depends on the initial and final states of the system.

The spontaneity of a reaction is explained by the standard gibb's free energy.

  • If Delta-G = -ve ( the reaction is spontaneous)
  • if Delta -G = +ve ( the reaction is non-spontaneous)
  • if Delta-G = 0 ( the reaction is at equilibrium)

The step by step calculations is done as shown in the attachment.

3 0
3 years ago
This picture shows students working in a
Lilit [14]

Answer:

yes it is true they apply necessary safety measures

8 0
3 years ago
Explain the role of carbon in mole calculation and definition
vichka [17]

Explanation:

I don't know.

the rock vs the world

4 0
3 years ago
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