<span>Average oxidation state = VO1.19
Oxygen is-2. Then 1.19 (-2) = -2.38
Average oxidation state of V is +2.38
Consider 100 formula units of VO1.19
There would be 119 Oxide ions = Each oxide is -2. Total charge = -2(119) = -238
The total charge of all the vanadium ions would be +238.
Let x = number of of V+2
Then 100 – x = number of V+3
X(+2) + 100-x(+3) = +238
2x + 300 – 3x = 238
-x = 238-300 = -62
x = 62
Thus 62/100 are V+2
62/100 * 100 = 62%
</span>62 % is the percentage of the vanadium atoms are in the lower oxidation state. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
<span>1.49 x 10^22 atoms
First determine the molar mass of P2O5
Atomic mass of Phosphorus = 30.973762
Atomic mass of Oxygen = 15.999
Molar mass of P2O5 = 2 * 30.973762 + 5 * 15.999 = 141.9425
Now determine how many moles of P2O5 you have
0.500 / 141.9425 = 0.003523
Since there's a total of 7 atoms per molecule of P2O5, multiply the number of moles by 7 to get the number of moles of atoms you have.
7 * 0.003523 = 0.024661
Finally, multiply by avogadro's number (6.0221409 x 10^23) to get the total number of atoms.
0.024661 * 6.0221409 x 10^23 = 1.48512 x 10^22</span>
Forms
Type of energy Description
Radiant potential energy stored in the fields of propagated by electromagnetic radiation, including light
Rest potential energy due to an object's rest mass
Thermal kinetic energy of the microscopic motion of particles, a form of disordered equivalent of mechanical energy
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