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IgorLugansk [536]
3 years ago
8

How do you use Reference Point in Science

Chemistry
1 answer:
Alika [10]3 years ago
4 0

Explanation:

A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. Objects that are fixed relative to Earth – such as a building, a tree, or a sign - make good reference points.

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Fe + H2SO4 = Fe2(SO4)3 + H2
a_sh-v [17]
C (667) that’s the answer boiii
5 0
3 years ago
How is the atomic mass of an atom calculated?
azamat
Adding the number of protons by the number of neutrons
8 0
3 years ago
A scientist is investigating the structure of aluminum nitrate, which has the chemical formula Al(NO3)3. Based on the chemical f
bekas [8.4K]
The chemical formula of aluminium nitrate is - Al(NO₃)₃
cation is Al³⁺
anion is NO₃⁻
One Al atom binds to three nitrate groups 
the options given are 
2. <span>It has three aluminum (Al) atoms 
this is incorrect as there's only one Al atom 
3. </span><span>It has one NO3 group.
this is incorrect as there are three nitrate groups
4. </span><span>It has nine nitrogen (N) atoms
there are only 3 N atoms therefore this too is incorrect 
</span>therefore the correct answer is - 
It has three NO₃<span> groups


</span>
6 0
3 years ago
An atom of argon has a radius rar = 88 pm and an average speed in the gas phase at 25°C of 172 m/s.
Rudik [331]

Answer:

1.2* 10³ rNe.

Explanation:

Given speed of neon=350 m/s

Un-certainity in speed= (0.01/100) *350 =0.035 m/s

As per heisenberg uncertainity principle

Δx*mΔv ≥\frac{h}{4\pi }

4π

h

..................(1)

mass of neon atom =\frac{20*10^{-3} }{6.22*10^{-23} } =3.35*10^{-26} kg

6.22∗10

−23

20∗10

−3

=3.35∗10

−26

kg

substituating the values in eq. (1)

Δx =4.49*10^{-8}10

−8

m

In terms of rNe i.e 38 pm= 38*10^{-12}10

−12

Δx=\frac{4.49*10^{-8} }{38*10^{-12} }

38∗10

−12

4.49∗10

−8

=0.118*10^{4}10

4

* (rNe)

=1.18*10³ rN

= 1.2* 10³ rNe.

Explanation:

This is the answer

7 0
3 years ago
A measured sample of argon gas has a volume of 20.0 L at a pressure of 660 mm Hg. What is the final volume
valkas [14]

Answer:

C . 24 L

Explanation:

Given data:

Initial volume of gas = 20.0 L

Initial pressure of gas = 660 mmHg

Final volume = ?

Final pressure = 550 mmHg

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

660 mmHg × 20.0 L = 550 mmHg × V₂

V₂ = 13200 mmHg. L/ 550 mmHg

V₂ = 24 L

3 0
3 years ago
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