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Ivan
3 years ago
9

Determine the cross product of x times y when x= 4i-5j+3k and y= -2i+3j-k

Mathematics
1 answer:
algol [13]3 years ago
7 0
\mathbf x\times\mathbf y=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\4&-5&3\\-2&3&-1\end{vmatrix}
\mathbf x\times\mathbf y=\begin{vmatrix}-5&3\\3&-1\end{vmatrix}\mathbf i-\begin{vmatrix}4&3\\-2&-1\end{vmatrix}\mathbf j+\begin{vmatrix}4&-5\\-2&3\end{vmatrix}\mathbf k
\mathbf x\times\mathbf y=-4\,\mathbf i-2\,\mathbf j+2\,\mathbf k
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Step-by-step explanation:

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Alice and Bob each choose at random a number between zero and two. We assume a uniform probability law under which the probabili
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Answer / Step-by-step explanation:

Before we start to answer this question, it would be nice to understand some basic definition and principles:

Random: This refers to an unpredictable pattern of arrangement.  Without a specific aim or logical procedural pattern.

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Uniform distribution is one of the widely used distributions although it's one of the simplest ones. The idea behind this distribution is that, unlike the other distributions, the likelihood of the any outcome in the distribution range is the same.

Now that we have a brief knowledge of the key terms within the question, hence, to start answering the question,

(a) Starting with 0 for Alice, Bob can choose any number starting from   1 /  3 . As Alice increases, Bob has to increase his starting point as well. Therefore, after Alice passes  1 /  3 , Bob can start choosing numbers from 0. This creates 2 triangles with sides  1  / 3 . The area of them gives us the probability.

Therefore, : P = 2 ( 1/3 1/3 1/3)

                        = 4/9

(b) We can find the probability of having both the numbers less than  1  / 3 . Then we subtract this probability from 1.

We have: P = 1 - 1/3 . 1/3

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(c) This is basically impossible as the area of a dot is negligible.

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8 0
3 years ago
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brilliants [131]

Answer:

proportion of gamers who prefer console does not differ from 29%

Step-by-step explanation:

Given :

n = 341 ; x = 95 ; Phat = x / n = 95/341 = 0.279

H0 : p = 0.29

H1 : p ≠ 0.29

The test statistic :

T = (phat - p) ÷ √[(p(1 - p)) / n]

T = (0.279 - 0.29) ÷ √[(0.29(1 - 0.29)) / 341]

T = (-0.011) ÷ √[(0.29 * 0.71) / 341]

T = -0.011 ÷ 0.0245725

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Using the Pvalue calculator from test statistic score :

df = 341 - 1 = 340

Pvalue(-0.447, 340) ; two tailed = 0.654

At α = 0.01

Pvalue > α ; We fail to reject the null and conclude that there is no significant evidence that proportion of gamers who prefer console differs from 29%

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