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wel
3 years ago
15

An athlete practicing for a track meet ran 400 meter in 50 seconds. What was his average speed?

Physics
1 answer:
sattari [20]3 years ago
7 0

Speed= Distance ÷ time

Speed= 400 ÷ 50 =8 m/s

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4A. How high is a 12 kg monkey in a tree if it has 509 J of gravitational potential Energy?
True [87]

4A. PE = MxGxH. (You can consider g as 9.8 / 10m/s as well)

509 J = 12x10xH

509 J = 120xH

H = 509/120

H = 4.24 m

Hope u got the answer....pls rate the answer if it is helpful for u....and I'm sorry I could not understand B part so I didn't do it.

Thank you

8 0
3 years ago
two cars go through 2 different crashes. car one 1 experiences a 500N impulse for a duration for 15s, while car2 experiences the
likoan [24]

Answer:

Conservation of momentum.

Momentum is zero after collision, no direction or speed.

Explanation:

7 0
3 years ago
What is the wavelength of a wave whose speed and period are 72.0 m/s and 5.00 s , respectively ?
uranmaximum [27]

Answer:

The distance between the two successive crests of the wave is 360m

Explanation:

Wavelength is defined as the property of wave in which the distance between identical points between two successive waves are calculated

Wavelength is referred to as the <em>distance between two successive crests or troughs</em>

<em>Given that:</em>

speed = 72.0 m/s

time = 5 seconds

Using the formula

C = fλ

Where C = speed, f = freequency and λ = wavelength

F = 1 / time

F = 1/5

F = 0.2Hz

From the fomula C = fλ

make λ the subject of the formula

λ = C / f

λ = 72/0.2

<em>λ = 360m</em>

3 0
2 years ago
Read 2 more answers
An object is dropped from the top of a tall building. At 2 seconds, it is 64 feet from the top of the building. At 4 seconds, it
jeka94

Answer:

96.21 ft/s

Explanation:

To solve this, you only need to use one expression which is:

Vf² = Vo² + 2gh

g = 9.8 m/s²

However, this exercise is talking in feet, so convert the gravity to feet first:

g = 9.8 * 3.28 = 32.15 ft/s²

Vo is zero, because it's a free fall and in free fall the innitial speed is always zero. With this, let's calculate the speed at 2 seconds, with a height of 64 ft, and then with the 256 ft:

V1 = √2*32.15*64

V1 = 64.15 ft/s

V2 = √2*32.15*256

V2 = 128.3 ft/s

So the average rate is:

V = 128.3 + 64.15 / 2

V = 96.22 ft/s

6 0
3 years ago
A man pulled a 13.0 kg object 11.8 cm vertically with his teeth. (a) How much work (in J) was done on the object by the man in t
jonny [76]

Answer:

(a)The work done by the man is -15.03J.

(b)The force exerted on the object is 127.4N.

Explanation:

Mass of the object pulled by the man is -13kg

Object is lifted 11.8 cm vertical with his teeth it means (displacement = +11.8cm = +0.118m)

Acceleration due to gravity is 9.8 \mathrm{m} / \mathrm{s}^{2}

(a) <u>Calculating the work done</u>:

Work done = mgh

Where "m" is mass of an object, "g" is acceleration due to gravity and "h" is the displacement.

\text { Work }=-13 \times 9.8 \times(+0.118 \mathrm{m})

\text { Work }=-15.03 \mathrm{J}

The work done by the man is -15.03J.

(b) <u>Calculating the force</u>:

Probably the man and the object are close to the exterior of the earth. If the rigidity required to maintained the object of consistent velocity interior the gravitational field of the earth is \mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}

Thus the weight of the object is balanced by the force of the man's teeth on the object. That is

F = mg

\mathrm{F}=13 \times 9.8

F = 127.4N

The force exerted on the object is 127.4N.

4 0
3 years ago
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