An object is dropped from the top of a tall building. At 2 seconds, it is 64 feet from the top of the building. At 4 seconds, it
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>
Height of Aeroplane = 500 meters
Speed of Aeroplane = 200 m/s
Acceleration due to gravity = g = 10m/s^2
time of package to reach the ground = t = ?
Horizontal distance = d = ?
<h2>_____________________________________</h2><h3>SOLUTION:</h3>When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the plane as the plane is just moving in horizontal direction. So the bomb fall and will travel forward.
Initial horizontal velocity is given by,
Initial vertical velocity is given by,
By the second equation of motion under gravity,
<u>For horizontal distance(d)</u>:
Horizontal distance has no acceleration thus d is given by
d = vt
d = 200x10
d = 2000 meters
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>
Answer:
The magnification is
Explanation:
From the question we are told that
The power of the lens is
Generally
The object distance is the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )
Generally the focal length is mathematically represented as
=>
=>
converting to cm
=>
Generally from lens equation we have that
=>
=>
Generally the magnification is mathematically represented as
=>
=>