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3 years ago

If Angle 8 is congruent to angle 10 and Angle 1 is congruent to angle 7, which describes all the lines that must be parallel?

Mathematics

2 answers:

timama [110]3 years ago

7 0

Answer:

C is the correct answer

Step-by-step explanation:

Misha Larkins [42]3 years ago

6 0

Answer: C is the correct answer Lines r and s and lines t and u must be parallel.

Step-by-step explanation: the step by step explanation is the the lines that answer C says are parallel

Lines r and s are crossed by lines t and u to form 16 angles. Clockwise from top left, at the intersection of r and t, the angles are 1, 2, 3, 4; at the intersection of s and t, 5, 6, 7, 8; at the intersection of u and s, 9, 10, 11, 12; at the intersection of u and r, 13, 14, 15, 16.

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Help on this one please?

Yakvenalex [24]

Answer:

The answer is 0.24.

Step-by-step explanation:

Hey there!

This question asks us to find products of two numbers given a table.

As we can see, we can find the product of each number if we separate them by whole integers and their decimal counterparts.

For instance, if we want to find the product of 0.8 and 1 using this table, we would find the cell that meets where 0.8 and 1 are together.

We see that the cell where 0.8 and 1 meet is 0.8, which is the product of the two values.

Therefore, if we want to find the value of the question mark, we just need to find the product of 0.8 and 0.3.

$0.8 \times 0.3 = \boxed{0.24}$

Therefore, the value for the question mark is 0.24.

5 0

3 years ago

Find the first six terms of the sequence. a1=-7, an=2*an-1

AlladinOne [14]

The first term of the sequence is $a_{1} = -7$ .

The sequences is recursive, every next term of the sequence is obtained by multiplying the previous term by 2.

So, we can find the next 6 terms as shown below:

$a_{2} = 2*a_{1}=2(-7)=-14$
$a_{3} = 2(-14)=-28$
$a_{4} = 2(-28)=-56$
$a_{5} = 2(-56)=-112$
$a_{6} = 2(-112)=-224$
$a_{7} = 2(-224)=-448$

3 0

3 years ago

Two surfers and statistics students collected data on the number of days on which surfers surfed in the last month for 30 longbo

Alisiya [41]

Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0: μL > μs against the claim Ha: μL≤ μs

the alternate hypothesis is the mean days surfed for all long boarders isless or equal to the mean days surfed for all short boarders (because long boards can go out in many different surfing conditions)

The test statistic is

t= x1- x2/ √s1/n1+ s2/n2

1) Calculations

Longboards

Mean

ˉx=∑x/n=4+8+9+4+9+7+9+6+6+11+15+13+16+12+10+12+18+20+15+10+15+19+21+9+22+19+23+13+12+10/30

=377/30

=12.5667

Longboard Variance S2=[∑dx²-(∑dx)²/n]/n-1

=[831-(-13)²/30]/29

=831-5.6333/29

=825.3667/29

=28.4609

Shortboard Mean

ˉx=∑x/n=6+4+6+6+7+7+7+10+4+6+7+5+8+9+4+15+13+9+12+11+12+13+9+11+13+15+9+19+20+11/30

=288/30

=9.6

Shortboard Variance S2=[∑x²-(∑x)²/n]/n-1

=[ 3270-(288)2/30]/29

=3270-2764.8/29

=505.2/29

=17.4207

2) Putting values in the test statistic

t=|x1-x2|/√S²1/n1+S²2/n2

t =|12.5667-9.6|/√28.4609/30+17.4207/30

t =|2.9667|/√0.9487+0.5807

t=|2.9667|/√1.5294

t=|2.9667|/1.2367

t=2.3989

3) Degree of freedom =n1+n2-2=30+30-2=58

4) The critical region is t ≤ t(0.05) (58) =1.6716

5) Since the calculated t= 2.4 does not fall in the critical region t(0.05) (58) ≤ 1.6716 we do not reject H0.

The p-value is 0.008969. The result is significant at p <0 .05.

6 0

3 years ago

An electric company charges a certain rate per kilowatt-hour (\text{kWh})(kWh)left parenthesis, start text, k, W, h, end text, r

Studentka2010 [4]

Step-by-step explanation:

The equation is given by :

63.25=800r+3.50

Here,

63.25 is the electric company charges

3.5 is an administrative fee

800 is charge per kilowatt hours

r is rate per kilowatt hour

In this proble, we need to tell that what does r represents. Hence, r shows kilowatt per hour.

We can solve it as follows :

63.25-3.5=800r+3.50-3.50 (Subtracting 3.50 to the both sides)

59.75=800r

$r=\dfrac{59.75}{800}\\\\r=0.0746$

8 0

3 years ago

A, B & C form the vertices of a triangle.

kirza4 [7]

<h3>Answer: 20.3</h3>

Work Shown:

tan(angle) = opposite/adjacent

tan(B) = AC/AB

tan(67) = x/8.6

8.6*tan(67) = x

x = 8.6*tan(67)

x = 20.2603303460843 ... make sure your calculator is in degree mode

x = 20.3 .... rounding to 3 significant figures

see diagram below

6 0

3 years ago