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Scrat [10]
3 years ago
7

Factor completely. y^2+6y+8

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0
(Y+4)(y+2) is this what it supposed to look like? Cause I don’t really remember.
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Write a decimal subtraction problem that requires regrouping to solve. then solve the problem
Svetach [21]
For example, think about 8.4 - 2.9.

You have to regroup because you can't subract 4 - 9.
4 turns into a 14 since you borrow from the left number, 8.
8 turns into a 7 after that.
Now, you have to subtract 14 - 9 and 7 - 2. You're answer is 5.5.
You can check your work by doing inverse opperations:
By adding:
5.5 + 2.9 = 8.4
Or by subracting 8.4 - 5.5 = 2.9

Hope this helped you! If you need a better explaination or another example, I will be happy to help you! :)
5 0
3 years ago
Find the product. (-3ab 2)3 27ab -23a2b2 -9a3b5 -27a3b6
horsena [70]

Answer:

Step-by-step explanation:

(-3 ab²)³=(-3)³(a)³(b²)³=-27 a³b^(2×3)=-27 a³b^6

8 0
3 years ago
Read 2 more answers
Find the measure of each angle using the triangle sum theorem and exterior angle theorem
Pani-rosa [81]
Just add all the numbers together and then multiple it by 3
5 0
3 years ago
A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
loris [4]

Answer:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of \frac{1}{2}.

Vertices of A' B'C' are

A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =  

The distance from A' to the origin is half the distance from A to the origin.

OA=\sqrt{(-4)^2+3^2}=\sqrt{25}=5\\\\ O'A'=\sqrt{2^2+(\frac{3}{2})^2}=\frac{5}{2}=2.5

8 0
3 years ago
Read 2 more answers
Please help me with this math problem
elena55 [62]

When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:


tangent line^2 = 8.45 * (8.45 + x)


13.5^2 = 71.4025 + 8.45 x


182.25 -71.4025 = 8.45x


8.45 x = 110.8475


x = 13.1180473373


x = 13.1 (rounded)


Source:

1728.com/circangl.htm




4 0
3 years ago
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