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satela [25.4K]
2 years ago
5

On the trip you and your friends stop for gas and decide to drinks 1.05, and snacks, which are 2.20, if they spend a maximum of

25$ and wish to buy at least 12 items , write a system of inequalities that show the range of drinks and snacks you can buy with 25.00, 2 inequalities are needed, and a data table for each
Mathematics
1 answer:
zysi [14]2 years ago
8 0
To be able to answer this item, we let x be the number of drinks bought. Similarly, we may represent the number of snacks by the variable y. The sum of the number of drinks and snacks bought should not be more than 12. This can be represented through the inequality,

    x + y ≤ 12

Furthermore, the total amount spent would be equal to the sum of the products of the number of the cost of each as represented in the inequality below.

     1.05x + 2.2y ≤ 25
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Answer:

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Step-by-step explanation:

∵ (t,17) lies on (x,y) plane y=x²-3x+7,t>0

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storchak [24]
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Someone please help me I don’t know this :(
Shalnov [3]

9514 1404 393

Answer:

  x = 10; WX = 5; HJ = 10

Step-by-step explanation:

The hash marks indicate that points W and X are midpoints of their respective segments. That makes WX a midline of the triangle. The midline is always half the length of the base (HJ). We can use this fact to write an equation relating the lengths.

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In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.
konstantin123 [22]

Answer:

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Step-by-step explanation:

Given

f(x) = 6x(1- x);\ 0 \le x \le 1

Required

P(0.3 < x < 0.7)

From the question, we have:

P(a < x < b) = \int\limits^b_a {f(x)} \, dx

So, we have:

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx

Open bracket

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx

Integrate

P(0.3 < x < 0.7) =  \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}

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Substitute 0.7 and 0.3 for x

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Using a calculator, we have:

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Remove brackets

P(0.3 < x < 0.7) =  0.784 - 0.216

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3 0
2 years ago
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