1. Given that e<span>vents A and B are dependent, P(A)=20%, P(BIA)=25%. What is P(A and B)?
P(BIA)=[P(A and B)]/P(A)
it follows then that:
P(A and B)=P(A)*P(BIA)
P(A)=0.2
P(BIA)=0.25
hence
P(A and B)=0.2*0.25=0.05=5%
2. Given that </span><span> P(A) =12%, P(B)=48% and P(A or B)=50%. What is P(A and B)?
P(A or B)=P(A)+P(B)-P(A and B)
but
P(A)=12%, P(B)=48%, P(A and B)=50%
thus
P(A or B)=12%+48%-50%
simplifying the above we obtain:
P(A or B)=60%-50%=10%
</span>
Well this is a hard question to answer, but this is how i would put it.
You would take a number (lets use 15) and the second number (lets use 5) would determine how many times it would go into 15. In other words, 5 time x would equal 15 (5x=15). 5, being a factor of 15, would evenly fit into 15 three times.
Answer:
There are 13 cards for each suit so the first fraction is 13/52 and the next one is 13/51 as there is no replacement for the first card you pulled.
Multiplying them you get: 13/52*13/51= 169/2652,
Then you divide both sides by 13 to get: 13/204
So, the answer is C.
I hope this helps!
Answer:
The following histogram shows the relative frequencies of the height recorded to the nearest inch of population of women the mean of the population is 64.97 inches and the standard deviation is 2.66 inches
(a) Based on the histogram, what is the probability that the selected woman will have a height of at least 67 inches? Show your work
Answer:
0.22268
Step-by-step explanation:
z-score is z = (x-μ)/σ,
where x is the raw score
μ is the population mean
σ is the population standard deviation.
(a) Based on the histogram, what is the probability that the selected woman will have a height of at least 67 inches? Show your work
At least means equal to or greater than 67 inches
z = 67 - 64.97/2.66
z = 0.76316
P-value from Z-Table:
P(x<67) = 0.77732
P(x>67) = 1 - P(x<67) = 0.22268
The probability that the selected woman will have a height of at least 67 inches is 0.22268
Step-by-step explanation:
