The approximate partial pressure of oxygen at 1500 m is 0.18 atm.
<h3>Pressure of the air</h3>
From barometric pressure table;
1500 m = 85 kPa
1 kPa = 0.0099 atm
85 kPa = ?
= 0.84 atm
Oxygen percentage in air = 21%
<h3>Partial pressure of oxygen in air</h3>
P = 0.21 x P(total)
P = 0.21 x 0.84 atm
P = 0.18 atm
Thus, the approximate partial pressure of oxygen at 1500 m is 0.18 atm.
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Answer:
<h2>A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. ... As the gas spins faster, it heats up and becomes as a protostar.</h2>
Explanation:
<h2>Read this and then choose your options ✍️✍️</h2>
HM, I think the answer would be D. This is just a guess, so please use it if ou want to answer D it's ok :D
Hey there!
Si₂H₃ + O₂ → SiO₂ + H₂O
Balance H.
3 on the left, 2 on the right. Add a coefficient of 2 in front of Si₂H₃ and a coefficient of 3 in front of H₂O.
2Si₂H₃ + O₂ → SiO₂ + 3H₂O
Balance Si.
4 on the left, 1 on the right. Add a coefficient of 4 in front of SiO₂.
2Si₂H₃ + O₂ → 4SiO₂ + 3H₂O
Balance O.
2 on the left, 11 on the right. We can't do this by simply adding coefficients to O₂ since 11 isn't divisible by 2. So we need to multiply the coefficients in front of everything else by 2 first.
4Si₂H₃ + O₂ → 8SiO₂ + 6H₂O
Now we can balance O properly.
2 on the left, 22 on the right. Add a coefficient of 11 in front of O₂.
4Si₂H₃ + 11O₂ → 8SiO₂ + 6H₂O
This is our final balanced equation:
4Si₂H₃ + 11O₂ → 8SiO₂ + 6H₂O
This means the coefficient for O₂ when the chemical equation is balanced is 11.
Hope this helps!
The volume of the 39% acid solution that Roger needs to use to make a mixture of 86 mL of a 36% acid solution is 74.27 mL.
The mixture of the acids solutions is given by:
(1)
Where:
C: is the concentration if the mixture = 36%
V: is the total volume of the mixture = 86 mL
C₁: is the concentration of acid 1 = 39%
V₁: is the volume if acid 1 =?
C₂: is the concentration of acid 2 = 17%
V₂: is the volume of acid 2
The sum of V₁ and V₂ must be equal to V, so:
(2)
By entering equation (2) into (1), we have:
Changing the percent values to decimal ones:
Now, by solving the above equation for V₁:
Therefore, the volume of the 39% acid solution is 74.27 mL.
To learn more about mixture and solutions, go here: brainly.com/question/6358654?referrer=searchResults
I hope it helps you!