I think it's A but it might be different from your school and mine
According to my calculations the correct Answer is C. +694. The answers A B and D Are incorrect. It cannot be A because I said it also cannot be B because C=H. The answer would not be D because balls in your jaws = +1192 And the answer will be CORRECT ANSWER C=+694
Answer:
d= 50.23 g/cm³
Explanation:
Given data:
radius = 137.9 pm
mass is = 5.5 × 10−22 g
density = ?
Solution:
volume of sphere= 4/3π r³
First of all we calculate the volume:
v= 4/3π r3
v= 1.33× 3.14× (137.9)³
v= 1.33 × 3.14 × 2622362.939 pm³
v= 1.095 × 10∧7 pm³
v= 1.095 × 10∧-23 cm³
Formula:
Density:
d=m/v
d= 5.5 × 10−22 g/ 1.095 × 10∧-23 cm³
d= 5.023 × 10∧+1 g/cm³
d= 50.23 g/cm³
Explanation:
It is known that charge on xenon nucleus is
equal to +54e. And, charge on the proton is
equal to +e. So, radius of the nucleus is as follows.
r = 
= 3.0 fm
Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.
d = r + 2.5
= (3.0 + 2.5) fm
= 5.5 fm
=
(as 1 fm =
)
Therefore, electrostatic repulsive force on proton is calculated as follows.
F = 
Putting the given values into the above formula as follows.
F = 
= 
= 
= 411.2 N
or, =
N
Thus, we ca conclude that
N is the electric force on a proton 2.5 fm from the surface of the nucleus.