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Nookie1986 [14]
4 years ago
5

What forces pushes protons in the nucleus apart

Chemistry
2 answers:
Nimfa-mama [501]4 years ago
7 0
Bring that ahs here boy 
alisha [4.7K]4 years ago
6 0
<span>Nuclear </span>force<span> is what holds atomic </span>nuclei<span> together in spite of the repulsive electromagnetic </span>force <span>between the positively charged protons that acts to </span>push<span> them </span>apart<span>.</span>
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Drying of lake beds :)
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4 years ago
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An unfortunate squirrel is hit by a car. A small bit of gas originally 0.005 L in volume is trapped in the squirrel's body at a
kykrilka [37]

Answer: The volume of the gas in the squirrel now is 0.00532 L

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=0.005L\\T_1=308K\\V_2=?\\T_2=328K

Putting values in above equation, we get:

\frac{0.005}{308}=\frac{V_2}{328}\\\\V_2=0.0053L

Thus  the volume of the gas in the squirrel now is 0.00532 L

3 0
3 years ago
The two major classes of telescopes are the _____ and the _____ telescope.
sukhopar [10]

Answer:

refractors and reflectors

Explanation:

4 0
3 years ago
How many moles of water, H2O, contain 2.0×1022 molecules of water? (See the hints for assistance in interpreting scientific nota
hammer [34]
You have to use Avogadro's number which is 6.02x10^23.  The units of Avogadro's number is molecules/mole so you divide the number of molecules by Avogadro's number which will give you the number of moles.
(2.0x10^22 molecules)/(6.02x10^23 molecules/mole)=0.033 moles
5 0
4 years ago
Consider stoichiometric combustion of gasoline and air. Assume a full tank of gasoline holds 50 L (approximately 13.2 gallons),
Inessa05 [86]

Answer:

520 kg

Explanation:

Let's consider the combustion of isooctane.

C₈H₁₈(l) + 12.5 O₂(g) → 8 CO₂(g) +  9 H₂O(l)

We can establish the following relations:

  • 1 mL of C₈H₁₈ has a mass of 0.690 g (ρ = 0.690 g/mL).
  • The molar mass of C₈H₁₈ is 114.22 g/mol.
  • The molar ratio of C₈H₁₈ to O₂ is 1:12.5.
  • The mole fraction of O₂ in air is 0.21.
  • The molar mass of air is 28.96 g/mol.

50 L of isooctane require the following mass of air.

50 \times 10^{3}mLC_{8}H_{18}.\frac{0.690gC_{8}H_{18}}{1mLC_{8}H_{18}} .\frac{1molC_{8}H_{18}}{114.22gC_{8}H_{18}} .\frac{12.5molO_{2}}{1molC_{8}H_{18}} .\frac{1molAir}{0.21molO_{2}} .\frac{28.96 \times 10^{-3}kgAir}{1molAir} =520kgAir

5 0
4 years ago
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