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katovenus [111]
2 years ago
13

This chemical equation represents a chemical reaction.

Chemistry
1 answer:
Strike441 [17]2 years ago
5 0

Explanation:

products are Nacl + H20

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The energy produced by the snack in an experiment is calculated to be 41,800 J/g. What is the energy of the snack in Calories/
Goryan [66]

The energy of the snack in calories per gram is 9983.3 Calories/gram.

<h3>What is the energy of a snack?</h3>

The energy that is contained in a snack is obtained from a calorimeter when the snack is burnt in a calorimeter. The mass of the snack that is burnt is measured in terms of energy output of the calorimeter.

If  1 calorie = 4.18J

x calorie = 41,800 J

x = 41,800 J * 1 calorie/4.18J

x = 9983.3 Calories/gram

Learn ore about energy in food:brainly.com/question/9602807

#SPJ1

5 0
2 years ago
According to model 1, how many grams of grass does herbivore a eat each day?
ICE Princess25 [194]
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3 years ago
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5 0
2 years ago
1. A crane lifts a 75kg mass a height of 8 m. Calculate the gravitational potential energy
koban [17]

Answer:

GP.E = 5880 j

Explanation:

Given data:

Mass = 75 kg

height = 8 m

Potential energy = ?

Solution:

The formula for gravitational potential energy is

GPE = mgh

m = mass in kilogram

g = acceleration due to gravity

h = height in meter above the ground

Formula:

GP.E = mgh

Now we will put the values in formula.

g = 9.8 m/s²

GP.E = 75 Kg × 9.8 m/s²× 8 m

GP.E = 5880 Kg.m²/s²

Kg.m²/s² = j

GP.E = 5880 j

6 0
2 years ago
A solution containing CaCl2 is mixed with a solution of Li2C2O4 to form a solution that is 3.5 × 10-4 M in calcium ion and 2.33
natka813 [3]

This is an incomplete question, here is a complete question.

A solution containing CaCl₂ is mixed with a solution of Li₂C₂O₄ to form a solution that is 3.5 × 10⁻⁴ M in calcium ion and 2.33 × 10⁻⁴ M in oxalate ion. What will happen once these solutions are mixed? Ksp (CaC₂O₄) = 2.3 × 10⁻⁹

A. Nothing will happen since both calcium chloride and lithium oxalate are soluble compounds.

B. Nothing will happen Ksp > Q for all possible precipitants.

C. A precipitate will form as calcium oxalate is not soluble to any extent.

D. A precipitate will form since Q > Ksp for calcium oxalate.

Answer : The correct option is, (D) A precipitate will form since Q > Ksp for calcium oxalate.

Explanation :

Concentration of Ca^{2+} = 3.5\times 10^{-4}M

Concentration of C_2O_4^{2-} = 2.33\times 10^{-4}M

The equilibrium chemical reaction will be:

CaC_2O_4\rightleftharpoons Ca^{2+}+C_2O_4^{2-}

The solubility constant expression for this reaction is:

K_{sp}=[Ca^{2+}][C_2O_4^{2-}]=2.3\times 10^{-9}

Now we have to calculate the ionic product for calcium oxalate.

Q_{sp}=[Ca^{2+}][C_2O_4^{2-}]

Q_{sp}=(3.5\times 10^{-4})\times (2.33\times 10^{-4)

Q_{sp}=8.2\times 10^{-8}

From this we conclude that, Q_{sp}>K_{sp} that means a white solid precipitate of calcium oxalate will be formed when the solutions are mixed.

Hence, the correct option is, (D)

4 0
2 years ago
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