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Nonamiya [84]
3 years ago
6

112,338 rounded to nearest 10,000

Mathematics
1 answer:
defon3 years ago
6 0

Answer:

110,000

Step-by-step explanation:

2 is lower than five so you have to round down

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Find the measure of the indicated angle.<br>​
tester [92]

Answer:

11) x = 21

12) x = 110

13) x = 85

14) x = 137

Step-by-step explanation:

Hope it helped <3

4 0
3 years ago
PLEASEE HELP WILL GIVE BRAINLEST 20 POINTS
Ket [755]
<h3>Answer:</h3>

For each birdhouse built, the total cost increases by $3.50.

<h3>Step-by-step explanation:</h3>

Let's try some of the answers and see if they work.

The "initial cost" will be the cost when 0 birdhouses are built.

... f(0) = 3.5·0 +24 = 24 . . . . . clearly, not $3.50

Then increasing the number of birdhouses by 1, the cost is ...

... f(1) = 3.5·1 +24 = 27.5 . . . . . the cost has gone up (not down) by $3.50

Clearly the total cost to build 1 birdhouse is not $3.50. (It is $27.50.)

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Our exploration of the formula leads us to conclude ...

... For each birdhouse built, the total cost increases by $3.50.

5 0
3 years ago
Please help. Sine and Cosine rules
kodGreya [7K]

Answer:

a=41.8 BC=2.8

Step-by-step explanation:

sin30/6=sinx/8

8*sin30=6sinx

4=6sinx

sin^-1(4/6)

angle a

cosine rule

bc^2=3^2 +5^2-2(3)(5)*cos30

BC^2=\sqrt8.019237886\\

BC=2.83

2.8

3 0
3 years ago
A card is drawn from a​ well-shuffled deck of 52 cards. Find the probability of drawing a diamond or a spade.
AveGali [126]

Answer:

2/13

Step-by-step explanation:

For a deck of card

Total cards = 52

Total spade = 4

Total diamond = 4

pr(drawing a spade) = number of spade/total cards

pr(drawing a spade) = 4/52 = 1/13

pr(drawing a diamond)  = 4/52 = 1/13

Pr(diamond or a spade) = 1/13 + 1/13 = 2/13

8 0
3 years ago
Please help me with this
jekas [21]

Answer:

The length= 16cm

The width= 6cm

The two long sides are 8cm both so 8 + 8 = 16

And the two short sides are 3cm both so 3 + 3 = 6

So your length should be 16cm and your width 6cm

I HOPE THIS HELPS! ∧   ∧

                              ⊂∵→ω←∵⊃

3 0
3 years ago
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