The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:

Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
x
5
Step-by-step explanation:
First choose a variable to represent the number,
Let's call it
x
We need to divide that number by
5
x
÷
5
or
x
5
is how you write it as an expression.
Circumference = π × diameter
π × 9 = 28.274333882
To 1dp = 28.3
Circumference = 28.3 inches
Answer:i THINK 79, i dont know fully, but i think 79
Answer:
4 hours
Step-by-step explanation:
In 6 hours, J paints 1 room
So, in 1 hour, J paints 1/6 th of the room
Using similar logic, in 1 hour, T paints 1/12 th of the room.
Working together in one hour, they paint (1/6+1/12) th =1/4 of the room.
1/4 of the room is painted in 1 hour
So, 1 room is painted in 1 1/4=4 hours