Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Answer:
137.5 Miles
Step-by-step explanation:
2 = 50 Right? So if you were to divide 50 by 2, you would get 1 = 25. All you would have to do from there would be to multiply 25 times 5.5 to get 137.5.
Answer:
if you are evaluating this claim is false
Answer:
-5 -2 3
The further down you go, the less it will be. so -5 would be the least, -2 would be in the middle and the greatest would be 3 because its positive
Let me know if u have anymore questions and plzzz mark brainlest and thank me
If the marker is 0.13cm, then it is 13 millimeters.