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Eduardwww [97]
3 years ago
5

A golden retriever is sitting in a park when it sees a squirrel. The dog starts running, exerting a constant horizontal force of

89 N against the ground for 3.2 seconds. What is the magnitude of the dog's change in momentum?
Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

284.8 kgm/s

Explanation:

Impulse: This can be defined as the product of force and time of a body. The S.I unit of impulse is N.s mathematically.

Impulse = Force × time

Change in momentum: This is the product of the mass of a body and its change in velocity. The unit of change in momentum is kgm/s.

Mathematically,

momentum = mass×change in velocity

Deduction from newton's second law of motion,

Impulse = change in momentum

Therefore,

Change in Momentum = Force×time

ΔM = F×t................. Equation 1

Where F = force = 89 N, t =time =  3.2 s.

Substitute into equation 1

ΔM = 89×3.2

ΔM = 284.8 kgm/s

Thus the change in momentum = 284.8 kgm/s

You might be interested in
A charge -353e is uniformly distributed along a circular arc of radius 5.30 cm, which subtends an angle of 48°. What is the line
vladimir2022 [97]

Answer:

- 1.3 x 10⁻¹⁵ C/m

Explanation:

Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C

r = Radius of the arc = 5.30 cm = 0.053 m

θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad        (Since 1 deg = 0.0175 rad)

L = length of the arc

length of the arc is given as

L = r θ

L = (0.053) (0.84)

L = 0.045 m

λ = Linear charge density

Linear charge density is given as

\lambda =\frac{Q}{L}

Inserting the values

\lambda =\frac{-564.8\times 10^{-19}}{0.045}

λ = - 1.3 x 10⁻¹⁵ C/m

4 0
3 years ago
An object of mass m is traveling on a horizontal surface. There is a coefficient of kinetic friction  between the object and th
Gnom [1K]

Answer:

8m * (μg/v)^2

Explanation:

k, the spring constant = ?

(k in terms of μ, m, g, and v.)

Frictional force = μmg

Note: lost KE is converted to work done against the friction + PE of the spring

1/2mv2 = μmgx + 1/2kx^2....equation i

Cancel the 1/2 on both sides

mv^2 = μmgx + kx^2

Lets recall that:

Due to frictional effect, further enegy will be lost when the spring recoils backward

Therefore

1/2kx^2 = μmgx..... equation ii

Let's substitute 1/2kx^2 in equation I for ii

So we can say that:

1/2mv^2 = (μmgx)+ μmgx

1/2mv^2 = 2 (μmgx)

1/4mv^2 = μmgx

Cancel out m on both sides

1/4v^2 = μgx

Make x subject of the formula

x = (1/4v^2) / (μg)...... equation iii

substitute x to equation ii

But first make k in equation ii subject of the formula

1/2kx^2 = μmgx

k = 2μmg/x

Now substitute x

k = 2μmg / ((1/4v^2) / (μg))

k = 2μmg * ((μg) / (1/4v^2))

k = 8m * (μg/v)^2

8m * (μg/v)^2

7 0
3 years ago
A force of 99 N causes a box to accelerate at a rate of 12 m/s2. What is the mass of the box?
ira [324]


m = F/a

m = 99/11 = 9

The answer is 9 Kg

5 0
3 years ago
A suspended object A is attracted to a charged object B, can one conclude that A is charged? Explain
irinina [24]

Explanation:

In my view, when the Object A is attracted to a Charged object B. Object B should be Negatively or Positively charged. So Object B should be the Opposite charged according to the Object B

Example =

If Object B is Negatively Charged, the Object A should be Positively Charged

If the Object B is Positively Charged, the Object A should be Negatively Charged

Sometimes it can Mix as a Neutral as well

Hope this Helps

5 0
3 years ago
In a given chemical reaction the energy of the products is less than the energy of the reactants. Which statement is true for th
Westkost [7]

Answer:

B. Energy is released in the reaction.

7 0
3 years ago
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