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umka21 [38]
3 years ago
8

Whats the standard unit for measuring mass

Physics
2 answers:
Nat2105 [25]3 years ago
7 0
The standard unit for measuring mass is kilograms.
stich3 [128]3 years ago
6 0
Kilograms


The kilogram is the SI base unit of mass and is equal to the mass of the international prototype of the kilogram, a platinum-iridium standard that is kept at the International Bureau of Weights and Measures (BIPM)

Hope this helps!
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6. Протон с кинетична енергия Ek = 1,6.10 J, който се
anzhelika [568]

Answer:

Tahukah kamu, mengapa motor berhenti di depan lampu merah?

karena motornya direm. Coba kalau nggak direm bisa bahaya tuh.

Tebak binatang apa yang jago renang?

Bebek. Kalau ikan bukan renang tapi menyelam

Kenapa di rel kereta api ditaruh batu?

Soalnya kalau ditaruh duit nanti pada diambil.

3 0
2 years ago
Can someone pleaseEeeeeeee ASAP answer this❗️❗️❗️❗️ I really need help it is my second time posting this❗️❗️❗️❗️
belka [17]

Answer:

Data:-vi=om/s (b/c as in question penny is dropped from building means before coming to ground its initial state or velocity was considered as zero ) now distance or height h=380m and now we have to find the final velocity vf=? and the time t=?

Explanation:

So applying second eq of motion s=vit+1/2×gt² (here we have taken a gravity b/c when ever body is in vertical position then acceleration due to gravity is applied ) s=0×t+1/2×gt² , s=0+1/2×9.8×t² ,380=4.9t² we have to find t so 4.9t²=380 , t²=380÷4.9 , t²=77.55 now sq root on b/s

\sqrt{t }  =  \sqrt{77.55}

so t=8.806s and now apply 1st eq o²f motion to find out vf so vf=vi+gt , vf=0+9.8×8.806 ,vf=86.298 and if you want to verify that either this is answer is correct or not so put the value of t in second eq of motion and if you got distance same as give in the question so your value of t is considered as correct likewise s=vit+1/2gt² , s=0+1/2×9.8(8.806)²,s=4.9×77.55 ,s=380m (proved) I hope it would be helpfull

3 0
3 years ago
PLEASE I NEED HELP!!!
lakkis [162]
Objects sink if they are denser than water
8 0
3 years ago
Find the minimum kinetic energy in MeV necessary for an α particle to touch a 39 19 K nucleus that is initially at rest, assumin
SIZIF [17.4K]

Answer:

KE = 9.6MeV

Explanation:

Given the relationships we understand that,

q_1 = 19e, q_2 = 2e

The Potential at point p, is given by the following formula

V_ {p} = \frac {Kq_1} {r}

According to the graphic designed, you have,

V_ {p} = \frac {Kq_1} {(r_1 + r_2)}

V_ {p} = \frac {(9 * 10 ^ 9) (19 * 1.6 * 10 ^ {- 15})} {(3.7 + 2) * 10 ^{- 15}}}

V_ {p} = 4.8 * 10 ^ 6V

The kinetic energy of the particle would be given by

KE = q_2 * V_ {p} = 2e * 4.8 * 10 ^ 6V

KE = 9.6MeV

4 0
3 years ago
A motor with an operating resistance of 32 ohms is connected to a voltage source. the current in the circuit is 3.8
Phantasy [73]

V = I · R = (3.8 Amperes) · (32 ohms) = 121.6 volts
5 0
3 years ago
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