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SOVA2 [1]
3 years ago
11

The school is about 1500 m away. you run toward the school with an average velocity of 3 m per sec. how long did it take you to

get to school in seconds
Physics
2 answers:
kramer3 years ago
5 0
500. You divide 1500 by three, because you are going 3 meters per second. This results in 500 seconds.
Mariulka [41]3 years ago
4 0
Yup I agree with that.

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A 70.0 kg person climbs stairs, gaining 3.90 meters in height. Find the work done (in J) to accomplish this task.
Veronika [31]

Answer:

Work done, W = 2675.4 J

Given:

mass, m = 70.0 kg

height, H = 3.90 m

Solution:

According to the question, as the person jumps the stairs up, there is an increase in the potential energy of the person which is provided by the work done in climbing the stairs and is given by:

Work done, W = mgH

where

g = acceleration due to gravity = 9.8 m/s^{2}[tex][tex]W = 70.0\times 9.8\times 3.90 = 2675.4 J

6 0
3 years ago
If a ball rolls off a 4m high table at 7m/s, how long will it take until it hits the floor
Semenov [28]
It will take at least 0.8
3 0
3 years ago
A Meteorite Strikes On October 9, 1992, a 27-pound meteorite struck a car in Peekskill, NY, leaving a dent 22 cm deep in the tru
vagabundo [1.1K]

Answer:

Acceleration of the meteorite, a=-38409.09\ m/s^2

Explanation:

It is given that,

A Meteorite after striking struck a car, v = 0

Initial speed of the Meteorite, u = 130 m/s

Distance covered by Meteorite, s = 22 cm = 0.22 m

We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :

a=\dfrac{v^2-u^2}{2s}

a=\dfrac{-(130)^2}{2\times 0.22}

a=-38409.09\ m/s^2

So, the deceleration of the Meteorite is -38409.09\ m/s^2. Hence, this is the required solution.

7 0
3 years ago
How are the mass and weight of an object related? Include a description with words and an equation.
nikdorinn [45]
The weight is the force experienced, whereas the mass represents the actual quantity of matter inside a body..
weigh on the surface of the earth is equal to mg
mass is m
and at the centre weight is 0 due to 0 acceleration that's 0 g
but mass is always constant and remains m, no matter where you are
6 0
3 years ago
You throw a baseball directly upward at time ????=0 at an initial speed of 14.9 m/s. What is the maximum height the ball reaches
xeze [42]

Answer:

Maximum height, h = 11.32 meters

Explanation:

It is given that,

The baseball is thrown directly upward at time, t = 0

Initial speed of the baseball, u = 14.9 m/s

Ignoring the resistance in this case and using a = g = 9.8 m/s²

We have to find the maximum height the ball reaches above where it leaves your hand. Let the maximum height is h. Using third equation of motion as :

v^2-u^2=2ah

At maximum height, v = 0

and a = -g = -9.8 m/s²

h=\dfrac{v^2-u^2}{2a}

h=\dfrac{0-(14.9\ m/s)^2}{2\times -9.8\ m/s^2}

h = 11.32 meters

Hence, the maximum height of the baseball is 11.32 meters.

8 0
3 years ago
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