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Stells [14]
3 years ago
5

А_is an area of land that rises very high above the land around it.

Physics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

A mountain is classified as landform that raises at least 1,000 feet or more above its surroundings areas of land.

Lelu [443]3 years ago
7 0
Answer:
А mountain is an area of land that rises very high above the land around it.

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Imagine a box sitting on a shelf. What forces are acting on the box?
romanna [79]

In case of an object sitting at rest on another base, there are two equal and opposite forces – Normal force and the gravity.

Answer: Option A

<u>Explanation: </u>

When an object is placed at rest position on another object, there is a force exerted by the surfaces of the two contact objects. This force is denoted as Normal Force.

When an object such as a box is placed on a shelf, its surface exerts a contact force on the base of the shelf- The Normal force directed upward. Meanwhile, the gravity stays at its action and tries to pull the box towards itself.  

Both of these forces however are equal and opposite and therefore, there is zero net force on the box. That's why it remains at rest, holding on Newton's third law.

3 0
3 years ago
HELP ME !!!! A.S.A.P!!!!! WILL BE MARKED AS BRAINLEST!!! 15 POINTS!!!!
Leni [432]

C is the correct answer. Opposites attract!

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3 years ago
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A 1100 kg car rounds a curve of radius 68 m banked at an angle of 16 degrees. If the car is traveling at 95 km/h, will a frictio
Mariulka [41]

Answer:

Yes. Towards the center. 8210 N.

Explanation:

Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.

In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.

The net force is equal to F = \frac{mv^2}{R} = \frac{1100\times (26.3)^2}{68} = 1.1\times 10^4~N

Note that 95 km/h is equal to 26.3 m/s.

This is the centripetal force and equal to the x-component of the applied force.

F = mg\sin(16) = 1100(9.8)\sin(16) = 2.97\times10^3

As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.

The amount of the friction force should be 8.21\times 10^3~N

Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.

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3 years ago
Two thermometers are calibrated, one in de
zlopas [31]
-40 c = -40 f but k would be 233.15
6 0
3 years ago
During an experiment, Ellie records a measurement of 0.0034 m. How would
Goshia [24]

Answer:

(A)   She needs to move the decimal point by 3 places

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