A farmer has a rectangle field with a perimeter of 5.4 miles and a length of 2.3 miles. Find the width of the field. The width o f the rectangle with perimeter P in length L is given by W equals P -2/2
2 answers:
Answer:
Step-by-step explanation:
perimeter = 2*(length + width)
53 m = 2*(2.3 m +w) . . . . an equation to find the width, w
26.5 m = 2.3 m +w . . . . . divide by 2
24.2 m = w . . . . . . . . . . . subtract 2.3 m
The width of the rectangle is 24.2 m
hope it helps
Answer: The width of the rectangle is 24.2 m
perimeter = 2*(length + width)
53 m = 2*(2.3 m +w) . . . . an equation to find the width, w
26.5 m = 2.3 m +w . . . . . divide by 2
24.2 m = w . . . . . . . . . . . subtract 2.3 m
The width of the rectangle is 24.2 m
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L = 2 + .5W 2L + 2W = 40 SOLVING (if needed) Substitute 2 + .5w in for l in the second equation and solve for w. 2(2 + .5w) + 2w = 40 4 + w + 2w = 40 Combine like terms and subtract 4 from both sides 3w = 36 Divide both sides by 3 w = 12 in. l = 2 + .5w l = 2 + .5(12) l = 8 in.
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