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motikmotik
3 years ago
11

Mark looked at the statistics for his favorite baseball player, Jose Bautista. Mark looked at seasons

Mathematics
1 answer:
tino4ka555 [31]3 years ago
6 0

⭕ <u>1</u><u>7</u><u>.</u><u>3</u>

<u>#</u><u>CARRYONLEARNING</u>

<u>{hope it helps}}</u>

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Step-by-step explanation:


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3 years ago
For breakfast, Clarissa can choose from oatmeal, cereal, French toast, or scrambled eggs. She thinks that if she selects a break
Leona [35]
No. If she selects a breakfast at random there is an equal chance she will select each item. 25% chance she will select oatmeal, 25% chance she will select cereal, 25% she will select french toast, and a 25% chance she will select scrambled eggs.
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5 0
3 years ago
Suppose that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage
Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29​%.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage of blue candies is equal to 29​%.

Let p = <u><em>population percentage of blue candies</em></u>

So, Null Hypothesis, H_0 : p = 29%     {means that the percentage of blue candies is equal to 29​%}

Alternate Hypothesis, H_A : p \neq 29%     {means that the percentage of blue candies is different from 29​%}

The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;

                         T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of blue coloured candies = 28%

           n = sample of colored​ candies = 100

So, <u><em>the test statistics</em></u> =  \frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }

                                    =  -0.22

The value of the z-test statistics is -0.22.

<u>Also, the P-value of the test statistics is given by;</u>

               P-value = P(Z < -0.22) = 1 - P(Z \leq 0.22)

                            = 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29​%.

4 0
3 years ago
Using elimination method, what will be the value of y after solving -x - y = 5 and -x + 4y = 15?
natka813 [3]

9514 1404 393

Answer:

  y = 2

Step-by-step explanation:

The variable x can be eliminated by subtracting the first equation from the second.

  (-x +4y) -(-x -y) = (15) -(5)

  5y = 10 . . . . . . . simplify

  y = 2 . . . . . . . . . divide by 5

4 0
3 years ago
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