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mario62 [17]
4 years ago
5

The total capacity of 6 jugs and 12 glasses is 21 litres. The capacity of the jug is 5 times that of a glass. Find the capacity

of each glass. Give your answer in litres
Mathematics
1 answer:
Gre4nikov [31]4 years ago
5 0
X-jugs
y-glasses

6x+12y=21l
x=5y

6(5y)+12y=21l
x=5y

30y+12y=21l
x=5y

42y=21l
x=5y


1l=2y
x=5y

x=12,5 l
y=2,5 l


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Tool bella bought 10 copies of jakes first CD at 14.56 cents per copy. how much did she spend
madam [21]
Answer is 145.6cents. If 1 copy is 14.56cents, it implies 10 copies = 10(14.56)
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3 years ago
4. A boat shop rents its boats for $20 per hour and charges a flat fee of
ruslelena [56]

Answer:

4 hours

Step-by-step explanation:

Let x = # of hours

22x + 10 = 98

       -10     -10

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8 0
3 years ago
The value of which of these expressions is closest to e?
mars1129 [50]

Answer:

B.

Step-by-step explanation:

Given: expressions

To find: the expression whose value is closest to e

Solution:

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\left ( 1+\frac{1}{19} \right )^{19}=\left ( \frac{20}{19} \right )^{19}=2.65\\\left ( 1+\frac{1}{22} \right )^{22}=\left ( \frac{23}{22} \right )^{22}=2.659\\\left ( 1+\frac{1}{20} \right )^{20}=\left ( \frac{21}{20} \right )^{20}=2.653\\\left ( 1+\frac{1}{21} \right )^{21}=\left ( \frac{22}{21} \right )^{21}=2.656

Therefore, value 2.659 is closest to the value of e.

So, option B. is correct.

7 0
3 years ago
What is 17.70 = 7/2m + 13.50 ?
Fantom [35]

<u>answer:</u>  m = 1.2

<u>work:</u>

17.70 = \frac{7}{2} m + 13.50  | subtract 13.50 and move it over

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6 0
3 years ago
HELP COLLEGE ALGEBRA
max2010maxim [7]

Answer:

1) \frac{-8}{11}  

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3) \frac{3}{4}

4) 0

Step-by-step explanation:

The slope formula of the line that pass across two points P1(x1,y1) and P2(x2,y2) is:

\frac{y2 - y1}{x2-x1} = slope

You can use this formula to solve all the four points:

1)

\frac{6- -2}{-9 - 2} = \frac{-8}{11}

2)

\frac{- 9.1 - 0.6}{-9.5 - - 1.9} = \frac{97}{76} =(Rounded)= 1.276

3)

\frac{2-5}{-2 -2} = \frac{3}{4}

4)

\frac{4-4}{-9 --4} = \frac{0}{-5} = 0 \\\\

3 0
3 years ago
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