Answer:
the correct answer is 38.0%
Step-by-step explanation:
Trust me
It is located in quadrant 3. Hope this helped :D
Answer:
Step-by-step explanation:
d(x)=√((x-2)2+(y-0)²)
=√((x-2)²+y²)
=√((x-2)²+(x-1)²)
=√(x²-4x+4+x²-2x+1)
=√(2x²-6x+5)
D=d²(x)=2x²-6x+5
0 × <span>0 = 0
0 </span>× <span>1 = 0
1 </span>× <span>1 = 1
Which means multiplication is closed under {0, 1}
</span><span>1 </span>÷ <span>1 = 1
0 </span>÷ <span>1 = 0
</span>
Division is not closed under {0, 1}
1 + 1 = 2
Addition is not closed under {0, 1}
0 - 1 = -1
Subtraction is not closed under {0, 1} either
So it's only A. Multiplication which is closed under {0, 1}
Answer:
x=2(twice)
y=0(twice)
Step-by-step explanation:
This question can be solved using substitution method
So let's solve
y=x+2....(1)
y=x2+5x+6....(2)
Substitute (1) into(2)
X+2=x2+5x+6
Collect like terms
X2+5x-x+6-2=0
X2+4x+4=0
X2+2x+2x+4=0
X(x+2)+2(x+2)=0
(X+2)(x+2)=0
X+2=0
Substrate 2 from both sides
X=-2
X+2=0
X=-2
Let's substitute the value of x into (1)
y=x+2
y=-2+2
Y=0(twice)
