What is the recursive formula for this geometric sequence? 4, -12, 36, -108, ...
2 answers:
You might be interested in
Correct Answer:
3rd option is the correct answer
Solution:
The zeros of the polynomial are -1,1 and 3. The multiplicity of 3 is 2. So the polynomial can be expressed as:
The y-intercept of the polynomial is -18. This means the polynomial passes through the point (0,-18). Therefore, y must be -18 when x = 0. Using these values of x and y in previous equation we get:
The final equation of the polynomial becomes:
3rd option is the correct answer
Solution:
The zeros of the polynomial are -1,1 and 3. The multiplicity of 3 is 2. So the polynomial can be expressed as:
The y-intercept of the polynomial is -18. This means the polynomial passes through the point (0,-18). Therefore, y must be -18 when x = 0. Using these values of x and y in previous equation we get:
The final equation of the polynomial becomes:
Answer:
67
Step-by-step explanation:
Assuming you require to simplify the expression.
Using the rule of radicals
×
⇔
Simplifying the radicals
=
=
×
= 6
=
=
×
= 11
Then
2 + 5
= 2(6 ) + 5(11
)
= 12 + 55
= 67