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Brums [2.3K]
3 years ago
8

Please solve!!! with working

Mathematics
1 answer:
lakkis [162]3 years ago
6 0

2fg+4g-6fg

(MINUS 6fg from 2fg)

-4fg+4g

(i would then put 4g- the common factor- outside brackets like)

4g(-f+1)

Step-by-step explanation:

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Use the method from the Example to approximate the solution to the equations below to two decimal places.
shutvik [7]

Answer:

The approximate solution of the equation is 4,29.

Step-by-step explanation:

The solve of this fomula is:

5ˣ = 1000

You can use log in each side of the formula::

log₁₀ 5ˣ = log₁₀ 1000

By logarithm law (logₐ (mⁿ) = n logₐ m. And as log₁₀(1000) = 3:

x log₁₀ 5 = 3

x = 3 / log₁₀ 5

x ≈ 4,29

Thus, the approximate solution of the equation is 4,29.

I hope it helps!

3 0
3 years ago
X-2y = 6<br> Зх — бу = 18<br> Solve using elimination
nalin [4]

Answer:

x-2y = 6

x=6+2y....,.........1

Зх — бу = 18.............2

putting the value of x in ..2

3(6+2y)-6y=18

18+6y-6y=18

0=o

8 0
3 years ago
Franklin walked 1/2 mile in 8 1/2 minutes. What is the unit rate in miles per minute ?
Alexus [3.1K]

.0588 miles per minute

Step-by-step explanation:

0.5/8.5 = ~.0588

8 0
3 years ago
sammi is trying to wrap a gift for her brother. the gift fits into a cube-shaped box with a side length of 9 inches. how many sq
Flauer [41]

Answer:

A=486\ \text{inches}^2

Step-by-step explanation:

The area of a cube shaped box is given by :

A=6s^2

Where

s is the side length and A is the surface area

We have, s = 9 inches

So,

A=6\times (9)^2\\\\A=486\ \text{inches}^2

So, the required area is 486\ \text{inches}^2.

8 0
2 years ago
The length of a rectangle is 2 meters less than 2 times the width. The perimeter is 20 meters. Find the width.
kakasveta [241]
The equation you'd make would be (2x-2)+(2x-2)+x+x=20 because the length is 2 m less than the width (x). To simplify, it'd be 6x-4=20 because you combine like terms. You then move the -4 over to the 20 to make it 6x=24. The final answer is 4 meters.
4 0
3 years ago
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