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Helen [10]
3 years ago
13

What are the impacts of the ph level rises in the sea

Chemistry
1 answer:
Kamila [148]3 years ago
5 0
High because obvs , ph is around the last letter in the alphabet so the ph is going to be high as well , hope this is correct
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A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
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Which segement of the heating curve shown above represents an increase in the potential energy, but no change in the kinetic ene
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When a reaction occurs between atoms with ground state electron configuration 1s2 2s1 and 1s2 2s2 2p5 the predominant type of bo
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Answer: The bond formed between the elements will be ionic bond.

Explanation: We are given two elements having electronic configurations:

Element 1: 1s^22s^1

Element 2: 1s^22s^22p^5

Element 1 can easily loose 1 electron to attain stable electronic configuration and Element 2 can accept 1 electron to attain stable electronic configuration.

For these elements, there will be a complete transfer of electron from Element 1 to Element 2. Hence, this will form a ionic bond.

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3 years ago
What is colligative property? why does theproperty changes the way that it does when the amount of solute is increased. State an
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Colligative properties are those substances that depend on the number of substances in the solution, not in the identity of that substance. The property changes the way that it does when the amount of solute is increased because it enables the solute to be scattered more. For example, the freezing point of salt water is lower than that of the pure water due to the salt ions present in water.

6 0
3 years ago
A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
AysviL [449]

Answer:- Heat lost by the metal is 279.45 cal.

Solution:- This type of problems are solved by using the concept, heat given = - heat taken

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the equation we use is, q=mc\Delta T .

where, q is the heat energy, m is mass, c is specific heat and \Delta T is change in temperature.

Combined mass of calorimeter and water is 250.0 g and the specific heat is \frac{1.035cal}{g.^0C} .

\Delta T  for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C

\Delta T  for metal = 11.08 - 45.00 = -33.92 degree C

let's plug in the values in the above equation and calculate heat gained by combined system.

q=250.0g*\frac{1.035cal}{g.^0C}*1.08^0C

q = 279.45 cal

So, the heat lost by the metal is 279.45 cal.


3 0
4 years ago
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