The percent yield : 73.5%
<h3>Further explanation</h3>
Given
Reaction
C+2H₂⇒CH₄
Required
The percent yield
Solution
mol of Carbon(as a limiting reactant) :
mol CH₄ based on C, and from equation mol ratio C : CH₄, so mol CH₄ = 8.3
Mass of Methane(theoretical yield) :
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The amount, in grams, of water, that the student originally started with would be 252 g
From the balanced equation of the reaction, the ratio of H2O to H2 is 1:1. Thus for every 1 mole of water that is separated, 1 mole of H2 is produced.
Recall that: mole = mass/molar mass
Mole of 28.0 g H2 produced = 28/2
= 14 moles
Equivalent mole of H2O would, therefore, be 14 moles.
Mass of 14 moles H2O = mole x molar mass
= 14 x 18
= 252 g
More on stoichiometric calculation can be found here: brainly.com/question/8062886?referrer=searchResults
It is B, and also for a moment I didn't understand that 4.69 x 10^22. I almost did this whole problem wrong.