Answer:
A solid residue of limestone and some gypsum.
Explanation:
In step 2, some of the limestone and gypsum in the chalk dissolve in the water. When the mixture is filtered, the dissolved substances remain in the water. When the water is boiled off or evaporated, the solid substances remain behind.
Answer:
In 1 mol of anything, you have 6.02×10²³ particles, so 1 mol of F₂ contains 6.02×10²³ molecules.
Answer:
K2 = 9.701 x 10^-10
Explanation:
K1 = 4.0 x 10^-5
K2 = ?
T1 = -10.8 °C +273 = 262.2K
T2 = -16 °C + 273 = 257K
ΔHrxn = 120. kJ/mol = 120000 J/mol
The formular relating all these parameters is given as;
ln( K2 / K1) = −ΔHrxn / R * (1 / T2 − 1 / T1)
ln (K2 / 4.0 x 10^-5) = - 120000 / 8.314 (1 / 257 - 1 / 262.2)
ln (K2 / 4.0 x 10^-5) = 1.1138
ln K2 - ln4.0 x 10^-5 = 1.1138
ln K2 = 1.1138 + ln4.0 x 10^-5
ln K2 = 1.1138 - 10.1266
ln K2 = -9.0128
K2 = 9.701 x 10^-10
