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True [87]
2 years ago
11

When sucrose is hydrolyzed, Choose... will be created as the glycosidic linkage is broken. Hydrolyzed sucrose Choose... give a p

ositive Benedict's test. Hydrolysis can be achieved by adding Choose... .
Chemistry
1 answer:
Flauer [41]2 years ago
6 0

When sucrose is hydrolyzed, <u>two reducing groups</u> will be created as the glycosidic linkage is broken. Hydrolyzed sucrose <u>will</u> give a positive Benedict's test. Hydrolysis can be achieved by adding <u>strong acids or enzymes.</u>

<h3>How is sucrose hydrolyzed in the body?</h3>

The reaction that breaks bonds and releases energy is called hydrolysis. It is a significant biological process that causes energy to be released from within our bodies. The human small intestine contains the -glucosidase enzyme sucrase, which hydrolyzes sucrose into its component monosaccharides fructose and glucose. In the brush boundary of the upper gastrointestinal system, roughly 10–25% of the fructose is converted to glucose.

To learn more about hydrolysis visit:

brainly.com/question/11461355

#SPJ4

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Which statement is best described as a atom
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a core of protons and neutrons surrounds by electrons

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3 years ago
How much energy is needed to vaporize 75.0 g of diethyl ether (c4h10o) at its boiling point (34.6°c), given that δhvap of diethy
malfutka [58]

Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

Explanation:

First we have to calculate the moles of diethyl ether

\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles

As, 1 mole of diethyl ether require heat = 26.5 kJ

So, 1.01  moles of diethyl ether require heat = \frac{26.5}{1}\times 1.01=26.8kJ

Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

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4 years ago
Which phrase is the best definition for the word common in environmental science?
andreev551 [17]
I believe that the best definition of the word common in environmental science is a typical resource. A typical resource is a resource that is not hard to find and is very common. The answer to the question will hence be A.
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7 0
3 years ago
Read 2 more answers
A sample of chemical X is found to contain 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen. The law of def
frozen [14]

Answer: 75 grams sample of chemical X should contain 21.43 grams of carbon

Explanation: The law of definite proportion states that a given chemical compound always contains its component elements in fixed ratio.

From the question, chemical X contains 5.0 grams of oxygen, 10.0 grams of carbon, and 20.0 grams of nitrogen.

Sum up the masses

5.0g + 10.0g + 20.0g = 35.0g

This means, 10.0 grams of carbon are present in 35.0 grams of chemical X.

Now, to the determine the mass of carbon that 75 gram sample of chemical X should contain,

According to the law of definite proportion, the component elements of a given chemical compound are in fixed ratio. Therefore,

If 35.0g of chemical X contains 10.0g of carbon

Then, 75 g of chemical X will contain

(75 × 10) / 35 g

= 21.43 grams

Hence, 75 grams sample of chemical X should contain 21.43 grams of carbon.

4 0
3 years ago
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Liquid octane (CH) has a density of 0.7025 g/mL at 20 °C. Find the true mass (murue) of octane when the mass weighed in 18 air i
Goshia [24]

Explanation:

According to Buoyance equation,

          m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]

where,      m = true mass

                 m' = mass read from the balance = 17.320 g

              d_{a} = density of air = 0.0012 g/ml

              d_{w} = density of the balance = 7.5 g/ml

                    d = density of liquid octane = 0.7025 g/ml

Now, putting all the given values into the above formula and calculate the true mass as follows.

      m = [m' \times \frac{1 - \frac{d_{a}}{d_{w}}}{1 - \frac{d_{a}}{d}}]    

          = [17.320 g \times \frac{1 - \frac{0.0012 g/ml}{7.5 g/ml}}{1 - \frac{0.0012 g/ml}{0.7025}}]

          = 17.320 g \times 0.999850                

          = 17.317 g

Thus, we can conclude that the true mass of octane is 17.317 g.

7 0
3 years ago
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