N oxidation number in N₂O = 1
S oxidation number in SO₂ = 4
S oxidation number in SO₃ = 6
P oxidation number in P₄O₆ = 3
Therefore, the Sulfur in SO₃ will not react with molecular oxygen as Sulfur is already using all of its valence electrons in bonding.
Mass number = number of protons + number of neutrons
mass number= 8 + 7= 15 ---> the answer is B.
Answer:
POSITIVE DESCRIBES AN INCREASE IN SPEED AND NEGATIVE DESCRIBES A DECREASE IN SPEED.
Explanation:
The options for given question are as follow,
1) Methane molecules show hydrogen bonding.
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).
Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
HCI are less soluble in water as the temperature of the solution is increased.
